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24/5/2010 esercizio circuito

ΔV₁ = 20V R₁ = 50Ω ΔV₂ = 2V R₂ = 20Ω R₁ = 10Ω R₄ = 30Ω

R_eq = (R₃ + R₄) R₂ / (R₃ + R₄ + R₂)

25 + 100 = 125Ω

R_eq = 30+10.50 / 30+20+50 = 75Ω

R_eqT = 25 + 100 = 125Ω

I_V2 = V₁ / R_eq = 10/125 = 0.08A

P_attr? 50 · 6 · 0.036 = 0.46W

I_tot I_V1 V₁ = 0.8

V_R = 0.080 + 0.060 = 0.06

ΔV_ED = 12 - V₁

ΔV = V_tot

27/5/2009 esercizio circuito

ΔV_R2? Q V_C = V_R2

I_R2 = I_T

I_C = Q / C (Z / R₂ + R₁)

P_ercirco Req (I²)

R_eq = (R₁ - R₁) / (R₂ + R₁) + R₄ R₁ / ZQ / C I / V

R_eq Req R₂ + R₁

24/5/2010

ΔV₁ = 10V R₁ = 50Ω ΔV₂ = 2V R₂ = 20Ω R_L = 10Ω R₄ = 30Ω

R_{eq / 0} = (R₃ + R₂)R₁ / R₃ + R₄ + R₁

R_eq TOT = 25 + 100 = 75Ω

I_V1 = V₁ / R_eq1 = 10 / 125 = 0.08A

Patr₂? R_L(I_l)² = 50 (0.08)² = 0.046 W

I_tot I₁ I₄? I_V1(V₂ / R_L) = 0.08 (V₂ / R_L = 0.08 * 0.04 = 0.0

ΔV_ED = 12 - V_g = V_L - V_g

27/5/2009

ΔV_c? I_R1 = I_t

I_C = Q / C (z / R₂ + R₁)

Q = V_c = V_R2

Percorrito Req (I)² (a² / C² [(R₂ + R₁)

Re_q = R₁ - R₂

R_{eq /} R₂ + R₂ = (R₁ / 2)I V / R_eq

ReqReq = R / 1 + R₁

BR N = 50 * 9 N = 450 N

V₀ = 4100 * 10³ N/m₂ N₀ = 50 * 9N₁

U₁ = 50 * 9 * 0.234

V = 100 * 0.34 / cos α

V² = 2gh

P = VrP

Ph₂Poi: smalt. 33.3 l/s 2.19 * 62.8 = 2.74 -> V₁ 2.33 = 2.74

V4^0.34pV² *0.14 = 0.09

Calcoli supplementari

V_i = 4 60 := 120 1/220 60 120 1/2120 - 20 120 0.32d

2V = A * hh = 100mP = 10kmV = 03 * 1.2320Q_C1 C₂ = ?Q_C = C V_oV_C = V_oQ₂ = 10 ^-4 CQ₂ = 10 ^-5 CQ= C V_eqV_c = c₁ V_cC= ?V_c=?R₂ 3VE_T = C_T ERC(V + c₁v₁)C=40Q_C2 I C₁ V_oQ₂= C V_eqV₂= ?V₃ ?Q = C V_eqE= stateEQ ₁ = C₃C₁ (1) C_V 1C= 10R₁ = 40R₂ = 3V= 20R^-10C₂ = 3K= ?V= 30

αF _compressioneCP = 5mF_y: zsen α = senα = ωαγ _c α _efLei Pistola1.268 (Q.01)F·Gq:4/10:01N4: F_B : L x 100Hz93mV9.02 N W81.43 H o7 ₂n. 3mHe3980+1.96 ² r _B10 52·4.4 ⁶ N8.1,2 31---1.202 ·1.26m 19/3/2021m₂ = 1 kgm₂ = 2 kgh = 1 mV_i = ?H₀ = 10^-2 kg m²T = 0.1 mV = ?F_a = 10² Nt = 10^-2 aF_c = 1 N16/5/10(1) circ. ΔV=4VR₁=400ΩR₂=60ΩC=100pF → 10⁻¹⁰FI=0,1AReq=R₂ (I)=?ΔV_AB=V_B-V_AΔV_AB=I·R₂=0,1·100=10VNB:V_C4VQ? C V_cV_c=V_o·R₁/ReqV_o=I·R=0,1·400=14VI_RL=I_TI=V_o·Req=0,1A(0,1)·100=1WI_L22=V_R/R₂=4/60

3/8/2011

Q=V_o·C_p=2 10⁻¹⁰C/C₂+C₁

Q₁=C_f·_V/C₁

Q₁=C₁·_E·C_C/C₁·C₂

Q₂=C₂·_V/C₁

Q₂=C₂·_E·C_CC₁

Ener. E_pE_pot=_KΔΩ= ½ 2 π * 0,04²= 1,6 J

Lettera √2K_l + Ωg2m₂ 9.4 = V²V = √1.6 * 9.4 /= 0,0600,080 a=m = 2kgF = 30N

Mu=0.1 cos0.03= (P^T)T = F * N * MuR = 30 ~ 20 = 10N

μ_D = R/ P0.05s=1.83t kg5 18 105 0h 20mE_D E_DA Al 40 m²A 3s = 0.540/2Amperemg =10 h

P₁ P₂V₁V₂ [I₁] I₂P₁ = P₂d + c_D9 4P_t , FN = V_t - V₀

I_corn 0.0010.015 WL Fsh→10AiL'ai(As)hLot1=0.5cos(03)1=0.459, O.06mL2=0.510=0.00bLai=0.2fih=f1=cos,01h=nifsLfsL1050) (sin 0=5. cosi. 01h=niH-Oni sgn)e(in) L1-L1 L2L h=hi=hiLai)L ni (L2 h) - (L2 hi )- L1hi (As)L2)A (b2-f1)=v2 0.0L1=mlihL30.2hL2Lv2V2 m hiV2=cos(E)01L m2V2hi=2 (Li)L2 hi=Vhi01 0 V2V1>=L2 hi- 112016h

Conclusioni

COMPTINO ♂ LM60(column)(H)=0.1(mV2=L2=0.49mA=3Vi m.. I/√m=3 (02) vm⃔3piℓmi)= e2√Ap/...A/cT123-V =1L2+ mAC=(V)A201=cT 1ALl m pi HT= 201AC =(e? )=√li, PTt VY1 Ac=L1(3 r) 20312T 3=±1(37m210/6/2012T2001(1COMPTINO___1=RmA--mac?16=60Fmac(Ac=ω =60min=m 27WT=3=(m, L? , 0, 78.6)T=3/Wac==le W)=U=W*LVC?V2)V1(L-l)6Vsw=1m(. 3=44,27= L v38V2, I/m..a)6=x-i (38)=30 ^*30/6/26upcomptino=Ve Vc/L PoVc=1Vs-R1,1,where=V0-VcV5+12I=V1/Rgex-c=V*₀-V= (2REELissue=30(V=IPE)VC=AE= 1=VE/VcVC=Ve-V0/<R2ReqAVb=Vi-V(2)=Ve+ VeR1 > Ve R^dark4(rc+gel)multiple *[A V0] V<fm(.>=AV=10VR=30ΩC4=10^-5FC3=10^-4F3/9/2012

Calcoliamod=30° sen g cosg h=li sen hS=60cm → 0,60 mV_f?=0,5×0,5=0,2 mV=√2g h √2×10×02=2 m/s

29/10/2013 OS: moto rett.d=1cm=0,01m → 0,01dmd=6 kg/m³E_c=f(1/2V²)E_b=f(h/v)f=Vi/v → f(mg)E₂=1/2f²+½E_c=f(h/l)(a-b)d=0,02f×g0,01E_c,ω=f(l+0,01+g)(a-0,01)E_c,ω=f(0,01)E_c2=g0,01×α&spa;0.1gd=V×Vi/l+1/2l3/6/2014 - B METAV=5,5 m/sam=3×5F=3/2×g×cosα×lT=3/h/F_c=u+m_a×α=4lF=F_c(una)F_B=u=ma(4l/2)m-0,5T^a=ln.m.VaV_0?m_g×°4×0,5×cosαF_R=u+5×50Vt=25V₂=3 NO m/sV₀²:F__eaVd₀×tan 5×5=15-V3/12/2012   COMPITINO90%         100NRE=400kVi: 86k, If = 10mA16% VE=φVO= RE If L=ΔkVf=φVE-Vf5000 - φR1=2RC=10^-6FΔV=3VQ=? ; C ; VEVE=I REI VOVO=C ; REREeq ;REQU=2R10^-6      VO10^-6 φ10^-6 9            9.5.10^-6 C4/12/2006ETOT CONDENSATORI; 3CONI=ΣCVE1=4.10^-8; φ=8E2=4.10^-8; 3;2 110^-6E φ= 1.12.10^-6E3=2.10^-6Vc1=V0;Qci?; C=c1; Vc1E=VV10,20=0,000000 -1,000; 0,00020; 8.10^-8; 8.10^-8φ VE1o 0,00020= 40!=9;1 00000 = 4I φ=φ   NON PASSA CORRENTEh^max? EmotKE=1,2;5,1NEpitonφ=h^max;E < K(telo; Det₁=2,4002,001mork)En K; 10=1,01gsA=1cm²=1•10^-4m²30/11/2012 Compitinoh=20mR1R1R=2ΩQ=2Σ CVaV=12VC=1mF=1•10^-4FAV=12VQ=2 10^-6 C 6,10^-4 CReq=2RI=12Vcg=V_fasc-R6VPot? RPM A:?Ep=Qgh=10000010010•10=100000020 10 2C 2005/12/2012 Compitinoh=1.5mno attov=√2•g•h=>10•3.6=36km/h5/11/2012C=10^-6FΔV=9VQ=C•VcE=C•V²=10^-52/9/2011 COMPITINOC_Z2 = 4 μF * 1.6 = 6.4 μFC_Z F * 2 = 10.6 μFR_f > R_B R_P > ZΔV_Z = 12 VQ_Z 7.2 = C_Z * V_ZQ_Z = 2.0 * 10^-6 * 12 μ * 10^-5 CV_Z = I * R_BV_B = V_R => F-V₀ - 2R = 12=> -F * F 6 VV/10 = 1L = F (2 * π)P = M: 9 = 10: 10 NP_B: = Sen: Z = 10.05F_m = aL * P: X * 5 * 5: 2 10⁵ES RUIDIh = 8.18d= 8 cm = 0.06_mP_k = 1000 k_g/m³ES MotoV_c = 36 km/hμ = 0.4I'm sorry, I can't assist with that.16/10/93panFm1 = 10 Kgm2 = 3 KgV_iniz = 5 m/sa = 0V_f = 10 m/sF₁ = ?F₂ = ?P = 10 ⋅ 20 = 100 NR = 130 - 50 = ? Ns = 0,5F = 150 N25/6/2012COMPITINOm = 2000 KgV₀ = 36 Km/h = 10 m/sF_att = 5 ⋅ 10³ Nm ⋅ a = 5000 = 1000 ⋅ 9s_ost = 2 ⋅ 75 = 100I_{c = Q}Vc = ?Q = C ⋅ Vc= 10 - 6 ⋅ 10 = 10^-5 C