ESERCIZIO 2_1
=
o
1 0.01745rad
o
α = 1 m
σ = 250 MPa
amm
=
E 210000 MPa
υ = 0,3
=
M ?
t E 210000
= = =
G 80770 MPa
υ
2 *(1+ ) 2 *(1+ 0,3)
1*0,01745 rad
θ −5
= = 1,745*10 mm
u 1000
σ 250
τ = = = 144,34 MPa
amm
amm 3 3
Sezione chiusa
M M l
d(s) ∑
θ = =
∮
t t i
u *2 *2
dt t
4 *G * A 4 *G * A i
θ
*2
4 *G * A *
=
M u
t l
∑ i
t i
− −
l 200 12 100 10
∑ = + =
*2 * 2 52,6
i
t 10 12
i
= − − =
* 2
A (200 12) *(100 10) 16920mm
−5
2
4 *80770 *16920 *1,475*10
= = =
M 30684600Nmm 30690Nm
t 52,6
M 30690000
τ = = = 90,69 MPa
t
max * 2 *16920 *10
2 * A *t
τ 144,34
υ = = = 1,59
amm
τ 90,69
max
Sezione aperta
M
θ = t
u G * J t
θ
=
M *G * J
t u t
1 1
∑ ⎡⎣ ⎤⎦
= = + + + + =
3 3 3 3 3 3
J * l *t * 94 *10 90 *12 188*10 90 *12 94 *10 229013Nmm
t i i
3 3
−5
= =
M 1,745*10 *80770 * 229013 322800Nmm
t M *t 322800 *12
τ = = =
t max 16,9 MPa
max J 229013
t
τ 144,3
υ = = = 8,55
amm
τ 16,9
max
ESERCIZIO 2_2
σ = 235MPa
s =
G 8000009 MPa
α = o
4
= =
L 2m 2000mm
Sezione aperta
α
M
θ = =
t
G * J L
t
α
=
M *G * J
t t
L
1 ⎡⎣ ⎤⎦
= − + − − + − =
3 3 3 4
J * (50 6) *14 (120 7 5) *12 (60 6) *10 120453mm
t 3
4 *0,01745*80000 *120453
= = =
M 336304Nmm 336,4Nm
t 2000
σ 235
τ = = = 135,68MPa
s
s 3 3
M 336400 *14
τ = = =
*t 39,1MPa
t
max max
J 120453
t
Trave a sezione costante
=
L 215mm
υ = 2
=
t ?
media
=
M 336400Nmm
t 1 1
∑
= =
3 3
J * l *t * 215*t
t i i
3 3
σ 235
σ = = = 117,5MPa
s
υ
amm 2
σ 117,5
τ = = = 67,8MPa
amm
amm 3 3
1 ∑ τ
= 3
M * l *t *
t i i amm
3
336400 *3
= =
3 3
t 69,23mm
215*67,8
=
t 4,206mm
ESERCIZIO 2_7
=
P 10000N
= =
b 1m 1000mm
= =
L 2m 2000mm
σ = 240 MPa
s = = = 6
M P * b 10000 *1000 10 *10 Nmm
t = = = = 6
M M P * l 10000 * 2000 20 *10 Nmm
f xx
= =
P T 10000N
y ⎡ ⎤
1 1
= + = + − +
3 2 3 2
J * B * H B * H * y 2 * *12 *100 100 *12 *(100 6)
⎢ ⎥
xx 12 12
⎣ ⎦
⎡ ⎤
1
+2 − − = =
3 4 6 4
* *(200 12 12) *10 *(176 *0 *10) 30321493mm 30 *10 mm
⎢ ⎥
12
⎣ ⎦
È una sezione chiusa
= − − =
* 2
A (100 10) *(200 12) 16920mm
Punto A 6
M 20 *10
σ = = =
( M ) * y *100 66,67 MPa
xx
zz xx 6
J 30 *10
xx 6
M 10 *10
τ = = =
( M ) 24,63MPa
t
t * 2 *16920 *12
2 * A *t
τ =
(T ) 0
σ σ τ
= + = + =
2 2 2 2
3* 66,67 3* 24,63 79,15MPa
id σ 240
υ = = = 3,03
amm
σ
s 79,15
id
Punto B
σ =
( M ) 0
zz xx 6
M 10 *10
τ = = = −29,55MPa
( M ) t
t * 2 *16920 *10
2 * A *t
T * S
τ =
(T ) xx
J * b
xx
= − = 3
S 100 *100 *50 80 *88* 44 190240mm
xx
= =
b 2 *10 20mm
10000 *190240
τ = = −3,17
(T ) MPa
6
30 *10 * 20
τ τ τ
= + = −3,17 + = −32,72
(T ) ( M ) (−29,55) MPa
t
σ τ
= = =
3 * 3 *32,72 56,67 MPa
id σ 240
υ = = = 4,24
amm
σ
s 56,67
id
ESERCIZIO 2_8
= =
L 3m 3000mm
= 6
M 60 *10 Nmm
t
σ = 355MPa
s =
E 206000 MPa
=
G 80000 MPa
Sezione A (sezione chiusa)
= − − =
* 2
A (160 14) *(140 16) 18104mm
6
M 60 *10
τ = = = (per avere il massimo uso lo spessore minimo)
( M ) 118,36 MPa
t
max t * 2 *18104 *14
2 * A *t
σ τ
= = =
* 3 118,36 * 3 205MPa
max
σ 355
υ = = = 1,73
s
σ
s 205
M l
∑
θ = t i
u *2 t
4 *G * A i
− −
l 140 16 160 14
∑ = + =
*2 * 2 35,96
i
t 14 16
i 6
60 *10 rad
θ −5
= =
*35,96 2,057 *10 mm
u 2
4 *80000 *18104
180 180 o
θ θ −5 −3
= = =
o * 2,057 *10 * 1,18*10 mm
π π
u
θ θ −3
= = =
o o
* L 1,18*10 *3000 3,54
Sezione B (sezione aperta)
υ υ
= = 1,73
SB SA
σ
υ = s
σ
SB σ 355
σ = = = 205,20 MPa
s
υ 1,73
SB
σ 205,20
τ = = = 118,47 MPa
max 3 3
M
τ = *t
t
J t
τ * J
=
M t
t t
1 1 1
∑
= = − + − =
3 3 3 4
J * l *t *(140 8) *14 * 2 *(160 14) *16 440810mm
t i i
3 3 3
118,47 * 440810
= = =
M 3263992Nmm 3264000Nmm
t 16
M 3264000 rad
θ −5
= = = 9,25*10
t mm
u G * J 80000 * 440810
t
180 180 o
θ θ −5 −3
= = =
o * 9,25*10 * 5,3*10 mm
π π
u
θ θ −3
= = =
o o
* L 5,3*10 *3000 15,9
1 1
∑ ⎡⎣ ⎤⎦
= = − + − =
3 3 3 4
J * l *t * (140 2,5) *3,2 * 2 (80 3,2) *5 6203,73mm
t i i
3 3
M 57540
τ = = =
( M ) 0,56 MPa
t
t * 2 *10368*5
2 * A *t
ESERCIZIO 2_9
=
L 900mm
=
G 80000 MPa
σ = 190 MPa
amm 180
θ = = =
o
2 2 * 0,035rad
π
L 2
θ θ θ
= +
* * * L
tot aperta chiusa
3 3
M
θ = t
aperta G * J t
M l
∑
θ = *
t i
chiusa *2 t
4 *G * A i
= =
M F *300 300F
t
= − − =
* 2
A (140 5) *(80 3,2) 10368mm
− −
l 80 3,2 140 5
∑ = + =
*2 * 2 115,095
i
t 5 3,2
i M M
900 2
θ = + =
* *115,095* *900
t t
tot 2
80000 *6203,73 3 3
4 *80000 *10368
−7 −9 −7
= + =
6,045*10 * M 2,01*10 * M 6,0651*10 M
t t t
θ −7
= =
0,035 6,0651*10 M
tot t
0,035
= =
M 57707Nmm
−7
t 6,0651*10
M 57707
= = =
F 192N
t
300 300
Sezione chiusa
=
F 191,8N
= = =
M F *300 191,8*300 57540Nmm
t = = =
M F * l 191,8*900 172620Nmm
xx ⎛ ⎞
1 1 1
= + = + − + =
3 2 3 3 4
J * B * H B * H * y *80 *140 80 *140 *0 *73,6 *130 73,6 *130 *0 4818400mm
⎜ ⎟
⎝ ⎠
xx 12 12 12
= − − =
* 2
A (140 5) *(80 3,2) 10368mm
Punto A M 172620
σ = = =
( M ) * y *70 2,51MPa
xx
zz xx J 4818400
xx
M 57540
τ = = =
( M ) 0,56 MPa
t
t * 2 *10368*5
2 * A *t
T * S
τ =
(T ) xx
J * b
xx
= − = 3
S 73,6 *5*(70 2,5) 24840mm
xx
= =
b 2 *5 10mm
191,8* 24840
τ = =
(T ) 0,099 MPa
4818400 *10
τ τ τ
= + = + =
(T ) ( M ) 0,099 0,55 0,649 MPa
t
σ σ τ
= + = + =
2 2 2 2
3* 2,51 3*0,649 2,75MPa
id
Punto B M 172620
σ = = =
( M ) * y *65 2,33MPa
xx
zz xx J 4818400
xx
M 57540
τ = = =
( M ) 0,87 MPa
t
t * 2 *10368*3,2
2 * A *t
T * S
τ =
(T ) xx
J * b
xx
= − = 3
S 80 *5*(70 2,5) 27000mm
xx
= =
b 2 *3,2 6,4mm
191,8* 27000
τ = =
(T ) 0,168MPa
4818400 *6,4
τ τ τ
= + = + =
(T ) ( M ) 0,168 0,87 1,038MPa
t
σ σ τ
= + = + =
2 2 2 2
3* 2,51 3*1,038 2,94 MPa
id
Punto C
σ =
( M ) 0
zz xx M 57540
τ = = = −0,87
( M ) MPa
t
t * 2 *10368*3,2
2 * A *t
T * S
τ =
(T ) xx
J * b
xx
= − = 3
S 80 *70 *35 73,6 *65*32,5 40520mm
xx
= =
b 2 *3,2 6,4mm
191,8* 40520
τ = = −0,25MPa
(T ) 4818400 *6,4
τ τ τ
= + = −0,25 − = −1,12
(T ) ( M ) 0,87 MPa
t
σ τ
= = =
3 * 3 *1,12 1,94 MPa
id
Sezione aperta
= + = 3
S 2 *140 *3,2 *70 73,6 *5* 2,5 63640mm
xx = = + =
S A* y (2 *140 *3,2 73,6 *5) * y 1264 * y
xx tot tot tot
=
63640 1264 * y
tot
63640
= =
y 50,35mm
tot 1264 ⎛ ⎞
1 1 1
= + = + − + =
3 2 3 3 4
J * B * H B * H * y *80 *140 80 *140 *0 *73,6 *130 73,6 *130 *0 4818400mm
⎜ ⎟
⎝ ⎠
xx 12 12 12
⎡ ⎤
1 1
= + = + − +
3 2 3 2
J * B * H B * H * y *3,2 *140 3,2 *140 *(70 50,35) * 2
⎢ ⎥
xx 12 12
⎣ ⎦
⎡ ⎤
1
+ + − = + = =
3 2 6 4
*73,6 *5 73,6 *5*(50,35 2,5) 1809432,427 843347,7467 2652780,174 2,66 *10 mm
⎢ ⎥
12
⎣ ⎦
1 1 1
∑
= = − + + =
3 3 3 4
J * l *t * 2 *(140 2,5) *3,2 *(73,6 3,2) *5 6203,74mm
t i i
3 3 3
2 2
= = =
M F * * l 191,8* *900 115080Nmm
xx 3 3
= = =
M F *300 191,8*300 57540Nmm
t
Punto A M 115080
σ = = − =
( M ) * y *(140 50,35) 3,88MPa
xx
zz xx 6
J 2,66 *10
xx
M 57540
τ = = = −29,68MPa
( M ) *t *3,2
t
t J 6203,74
t
τ =
(T ) 0
σ σ τ
= + = + =
2 2 2 2
3* 3,88 3*(−29,68) 51,55MPa
id σ 190
υ = = = 3,68
adm
σ
s 51,55
id
Punto B M 115080
σ = = − =
( M ) * y *(70 50,35) 0,85MPa
xx
zz xx 6
J 2,66 *10
xx
M 57540
τ = = = −29,68MPa
( M ) *t *3,2
t
t J 6203,74
t
T * S
τ =
(T ) xx
J * b
xx
= + = 3
S 70 *3,2 *(35 19,65) * 2 24483,2mm
xx
= =
b 2 *3,2 6,4mm
191,8* 24483,2
τ = = −0,28MPa
(T ) 6
2,66 *10 *6,4
τ τ τ
= + = −0,28 − = −29,69
(T ) ( M ) 29,68 MPa
t
σ σ τ
= + = + =
2 2 2 2
3* 0,85 3*(−29,69) 51,43MPa
id σ 190
υ = = = 3,70
adm
σ
s 51,43
id
Punto C M 115080
σ = = = −2,18MPa
( M ) * y *50,35
xx
zz xx 6
J 2,66 *10
xx
τ =
(T ) 0 M 57540
τ = = =
( M ) *t *5 46,37 MPa
t
t J 6203,74
t
σ σ τ
= + = + =
2 2 2 2
3* 2,18 3* 46,37 80,34 MPa
id σ 190
υ = = = 2,36
adm
σ
s 80,34
id
ESERCIZIO 2_10
= =
N P 44000N
z
= =
T P 44000N
y y
= =
T P 11000N
x x
= = = 6
M P * b 27500 * 400 11*10 Nmm
xx y
= = = 6
M P * b 27500 * 400 11*10 Nmm
xx y B
= + − = + − =
M P *(c ) P * a 44000 *(200 40) 11000 *700 2860000Nmm
2
yy z x
B
= + = + = 5
M P *(c ) 27500 *(200 40) 66 *10 Nmm
2
t y
1 1 1
= + = + − + =
3 2 3 3 4
J * B * H B * H * y *80 * 200 80 * 200 *0 68*184 68*184 *0 18032810,67mm
xx 12 12 12
1 1 1
= + = + − + =
3 2 3 3 4
J * H * B B * H * x * 200 *80 80 * 200 *0 184 *68 68*184 *0 3712042,667mm
yy 12 12 12
= − − = =
* 2
A (200 8) *(80 6) 192 *74 14208mm
= − = 2
A 200 *80 68 *184 3488mm
Punto M N 44000
σ = = = −12,61MPa
(N ) A 3488 6
M 11*10 184
σ = = =
( M ) * y * 56,12 MPa
xx
xx J 18032810,67 2
xx
M 2860000
σ = = =
yy
( M ) * x * 40 30,82 MPa
yy J 3712042,6667
yy
σ σ σ σ
= + + = −12,61+ + =
(N ) ( M ) ( M ) 56,12 30,82 74,33MPa
xx yy 5
M 66 *10
τ = = =
( M ) 38,71MPa
t
t * 2 *14208*6
2 * A *t
T * S
τ = y xx
(T )
y J * b
xx ⎛ ⎞
8
= − = 3
S 80 *8* 100 61440mm
⎜ ⎟
⎝ ⎠
xx 2
= =
b 2 *6 12mm
27500 *61440
τ = = −7,81MPa
(T )
y 18032810,67 *12
T * S
τ = x yy
(T )
x J * b
yy
= − = 3
S 184 *6 *(40 3) 40848mm
yy
= =
b 2 *6 12mm
11000 * 40848
τ = = −10,09
(T ) MPa
x 3712042,667 *12
τ τ τ τ
= + + = − =
( M ) (T ) (T ) 38,71− 10,09 7,81 20,81MPa
t x y
σ σ τ
= + = + =
2 2 2 2
3* 74,33 3* 20,81 82,61MPa
id σ 355
υ = = = 4,30
s
σ
s 82,61
id
Punto N N 44000
σ = = = −12,61MPa
(N ) A 3488 6
M 11*10 184
σ = = = −56,12
( M ) * y * MPa
xx
xx J 18032810,67 2
xx
M 2860000
σ = = = −30,82
yy
( M ) * x * 40 MPa
yy J 3712042,6667
yy
σ σ σ σ
= + + = −12,61− − = −99,55MPa
(N ) ( M ) ( M ) 56,12 30,82
xx yy 5
M 66 *10
τ = = = −38,71MPa
( M ) t
t * 2 *14208*6
2 * A *t
11000 * 40848
τ = = −10,09
(T ) MPa
x 3712042,667 *12
27500 *61440
τ = = −7,81MPa
(T )
y 18032810,67 *12
τ τ τ τ
= + + = −38,71− − = −56,61MPa
( M ) (T ) (T ) 10,09 7,81
t x y
σ σ τ
= + = + =
2 2 2 2
3* (−99,55) 3*(−56,61) 139,73MPa
id σ 355
υ = = = 2,54
s
σ
s 139,73
id 5
M l 66 *10
∑ rad o
θ −6 −4
= = = =
8,3487 *10 4,784 *10
t i mm mm
u *2 2
t
4 *G * A 4 *80770 *14208 *82,5
i
E 210000
= = =
G 80770 MPa
υ
2 *(1+ ) 2 *(1+ 0,3)
⎛ ⎞
l 192 74
∑ = + =
* 2 82,5
i ⎜ ⎟
⎝ ⎠
t 6 8
i
θ θ −4
= = = o
* L 4,784 *10 * 400 0,191
tot u
ESERCIZIO 3_1
α = 0
30
σ = 180 MPa
p,o
2 N
γ = 10000 3
m
υ = 3
s σ 180
p,o
σ = = = 60 MPa
2
υ
t 3
s
= ∞
R
m 8000
= = = =
R R R 4000mm
A B t 2
R
=
R C
α
tC cos α
= = =
o
R H *tg 4500 *tg30 2598mm
c C α
W *tg 2598
= = =
R 3000mm
c α
tC o
cos cos(30 )
Punto A
= ∞
R
m σ σ
P = +
t m
t R R
t m
P * R
σ = t
t t
P * R
σ = tA
tA t A
P * R H * R 2500 * 4000
γ −9
= = = =
t * 10000 *10 * 1,6mm
tA A tA
σ σ
A 60
tA tA
Punto B (sotto i vincoli)
γ σ π
+ =
(V V ) * 2 * * R *t
1 2 m B
π 2
* R * h
=
V B cono
1 3
R 4000
= = =
h 6928mm
A
α
cono o
tg tg(30 )
π
= 2
V * R * h
2 B cilindro
=
h 5000mm
cilindro
⎛ ⎞
π 2
* R * h
γ π σ π
+ =
2
* R * h * 2 * * R *t
B cono
⎜ ⎟
B cilindro m B
3
⎝ ⎠
R * h
γ γ σ
+ =
* * R * h * 2 *t
B cono B cilindro m
3
⎛ ⎞
R * h 1
σ γ
= + R * h *
B cono
⎜ ⎟
⎝ ⎠
m B cilindro
3 2 *t
P * R h * R
σ γ
= = *
t cilindro B
t t t
σ σ σ σ σ σ
= + − =
2 2 *
IDVM m t m t amm
2 ⎡ ⎤
⎛ ⎞ ⎛ ⎞ ⎛ ⎞
γ γ γ
2 2 2 2 2
* R h * R * h h * h * R
1
σ γ −9
= + + + − +
h * R * R * h * * *10
B cono B cil cono cil B
⎢ ⎥
⎜ ⎟ ⎜ ⎟ ⎜ ⎟
⎝ ⎠ ⎝ ⎠ ⎝ ⎠
amm cil B B cil
2 2
3 3 2 *t t
4 *t t ⎣ ⎦
⎛ ⎞ ⎛ ⎞
2
R h h * h h h
1
γ −9
= + + + − +
2 2
* * * 2 * h h h * *10
B cono cono cil cono cil
⎜ ⎟ ⎜ ⎟
⎝ ⎠
cil cil cil
t 4 9 3 3 2
⎝ ⎠
⎛ ⎞ ⎛ ⎞
2
R h 2 * h * h h h
1
γ −9
= + + + − +
2 2
t * * * h h * h *10
B cono cono cil cil cono
⎜ ⎟ ⎜ ⎟
σ ⎝ ⎠
cil cil cil
4 9 3 2 3
⎝ ⎠
amm ⎛ ⎞ ⎛ ⎞
2
10000 * 4000 1 6928 2 *6928*5000 5000 6928 −9
= + + + − + =
2 2
t * * 5000 5000 * 5000 *10 2,98mm
⎜ ⎟
⎜ ⎟ ⎝ ⎠
⎝ ⎠
60 4 9 3 2 3
ESERCIZIO 3_2
N
γ = 10000 3
m
σ = 200 MPa
p,o
2
υ = 3
s =
F 1500KN
σ 200
p,o
σ = = = 66,7 MPa
2
υ
amm 3
s
⎡ ⎤ ⎡ ⎤
D 5000
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