Esercizi su turbine idrauliche

## TURB IDRO_ 28/06-2023 # #

N=37

Pu = 18 MW; Q = 26,7 mils; B = 0,21; m = 253,7 2pm { = 0,95 Neu = 0.91

D = 186m

=

Da

D2 = 2/4 m; us/c1 = cosas e cm2 = C sends by = 0,85 nv = 1

α2=

Q = { TO D B C sends

x =

Hu=

D1

Cmz

u1=

RCD1M

224,708

60

42 = R2D2M = 31,881

60

Cm2 = L Slud =

22

02-70

CL

W

Wz

1→

42

Cu2

= 12,314 m/s = W1

C = √42+2 = 27,607 mls

α = czce (m2) = 26,4903"

(Lilot Pu

= 740,832 J/kg >QUERO (Liba = Cuill - Cuz uz

Cu = Cuills - Rija - - 4,0335 μ

u2

con Cui=11

(92-90)-> Orecty

= 18,3672

Cm2.

α2=108,367 )

Hu = Li = 88,8719 i

22y

X = (Libott - 2

(C: Jatt

(04856145

# # TURB- IDRO-20-10-2013 # #

PELTON

Az = 420m; c1 = 36m/s, d = 0.11 m; 20 = 998, B = 16; 4/01 = 0,49; W = 0,92 WL

Trasaurs E.cin & Pendite Coudatt formats hw[ny=

Q = 55% Q noost, pelimu., not no

Pu=

MW]

4 = (1.049 42.14 m/s

20

(Li)att = u(c -u) (1+ \cosß ) = 3482, 7974/0

Az = Hd

Hd-X = 14 = 420m)

Perdita

pudar

foote

W

=

(Li Jatt

Hu

=

0845556)

4 = √24 / 2 (1 + 4 COSB) 4 (1-4) = 0,94752578 e

Lwg = ghug - 2 w2 - 2 = 147.740135/16

W

Lud = 2 hud = 2 [ 276 2 - €1 ] = (420, 93404 J/17)

Q = 0,55 Q = 0,44950693 m /5

Pi = 2yJpg Hu = 1565440, 232 W

P: Pe

; Lud

;Lug=

We

12

1=41-4 = 43,86 m/s

15= 444 = 40, 3512 w/s

Q = Th c = 081728533

Pu = 2y2pg Hu 20 =

=2789 508,06

= 279 MW

W

Pme = Pi - Pu = P (1-10)=??y@pg Hu (1-n) = 56 928, 735 W

Pu= 1,508 MUX

7

PELTON

N=39

## TURB_IDR - 20/01/2023 ##

Zlain te

d = 0,12 12 y = 0,89 / 20 = 0/ 98 B = 16", U/C1 = 0,49, W = 0,969 W1

Troscure Pessite Condotter forrot Y C = 168 m/s

Hu- Hol

V

Pu =

ba; Ling =

[J] V

4= 0,969

WAPd=

induzione pressione galo distributore

MWY

Q = 0,561Q; M=m; de y eat. Fu =

U = 0,49 (1

~=0967

WL

11

2y = 29 (1 + Ycosß) 4 (1- ~ ) 9 = nu

CL

C--)

W = C -U = 85,68 e W = 33,02372 m/s

( = 4 2gitu =>

Q = Tod C = 1,9 m /s

4

Pu = no Pi = n/ No My @pg Hu = 25,36 MW

UGELLO DISTRIBUTORE

hwoust = PO-PL + 1529

f-a

Pg.

C W

hund =

Hu = (C ) 1 = 1560 7994 m

= 996018

U= 82,32 m/s

PB-P = AP = (hursis + C+ ) Pg. = (153,1 ba

22

( 32-1) = 121,82721 uu

GIRANTE

+

huy = y (42-1) = ... Luey = gliw = (224,0 5/13

• REGOLAZIONE

Q = 1, 0659 m /s Pi = nuhy Qpg Hu = 258 337MW Pm = Pi-Pu = 0,5€3/ NU

Pi = nuly Q' pp Hu = 14,521 HW

Pu= Pi-Pm = 14 MW)

·è sempie

queno-

FRANCIS

D = 2,8 m

# # TURE_IDRO_31/03/2023 # #

Pu=20MW = 25 pen Q = 30 m /s

x= 100 ; D2 = 2,2m. 2y= 989, 2mm = 996;

perdute. adduzione Trasc. { = nv = 1

[α1 = 16.94 ; 4 = 0,3496; Hd = 79,57m]

•REGOVE

Salts

disponibile

4=0,97

a = 280 Q = cost, c1 = C [W} = 18,70 m/s]

4 = DIMTO = 36,6519 m/s

60

U = D mit = 28,7979 wls

60

Q = π B D (Cesenal Cre

D1

C

N=0

B/D = 0,22; Wer = W2m

hue=:

we = 2,5m

W

C1=CM2

V

α1

• Cr = Q

U

TUB DE

DL

= 5,53654

L> C = cm = 5,6219/5

Tos (10)

Cu2=-(2 Seu (10) = -0,9762 4/5 →→

Cu = (Lido

Uz

(L )ott - Cuili-Cuz Uz

Pu = new Qp (Lila

De au

+ Cuz Uz = 18,18 m/s + (LideπT = 694,4445/46

us

x = x (fre) ~ (16,24")

H = Hd - X

Hu = (Litt = 79,563) m

My 2

(L jett = 2 (HuΣhw) → Elus =

huw = (1 (2-1) = 1,15607m

29

Hu - Lija = 8,75195

2

hug = Σhw-hwi-hwe = 5, 19583 u

fiwg = w w → W = ? = 42 +16421 = 29,7741

2242 20

Wm2 = Cr = 55365 w/s

Y = 22

√2g (hug + w 2)

=0,9496

W2=√ 4 = 30,2845 m/s