Prove d'esame Matematica

DERIVABILED ≠ IN0 1 1,0≠x ✗- (b)f- )fla 1(c)f' U - 3= - = =b- a 1)C2 362S2C 2+ s3 (Zctl +zc- == _-,)( c' S?c- 6C +3 +2C3C O, =---? C2 2C2C 2 I o4C = =O -- -- 8 Fe±2 it=C. =a 2 Fa1-| t 2T dtDXdi S✗SU ==×✗ --.. t' S✗= -5)t' t.lt/ t'( dt +5✗+ = 2ft 10ft/ ') "t' sta dt2) dt dt(t' t' dts ++2+ ' 3(≥ 5)ts tot )(2 toS ×2 c > -x+ + a- ++3s g 3'{)f( ≥= ✗✗ i+2×S -. g)( '' §' Za+✗ I

2aper =- 6.09.21DELTEMA 2+2×-3)f( ✗1 =×. 2×+4 ( (-2,1-0)) 2)D=D: 21×+22×+4+-0 -1-0 io -- ,f- ( ) 2+2×-3 1≥ ±-2≥ UO o =✗ ✗N× ✗ = 1-3: V ✗ ≥≤✗e i2 ✗ 3= -a ???- -02×+4 > ✗ > -2D:)(A 0-3 , )( 1B 0 +t --, 2+2×-3✗Un a= -2×1-4so✗ → - 2+2×-3Un ✗ oo+=✗ 2×+4so+→ 2+2×-3 S -✗ - 32- U -un - si= - +== ±2×+4 -U '2- 0✗ tu AS VERTICALE2.✗-→ - = - .2+2×-3 St2+-4+-3✗Un so- === -" 2×+4 O'✗ -2 -U' tu-→ - )¥2+2×-3 ¥(☒ l'un ✗ ↓- 12- m→ -= =È' )¥/=D 2×2✗ ux→ 2. ++2+2×-3 2×2+41×-6 2¥ 4UX 6 ✗Un ✗ -{ -= -✗ =_± • )( 4×+4✗ → 2 ✗ +2×+4 2. 0u 0 12{6 OBUQUO Y 4AS= 2= o ✗- =→.± a ) ?( '(2×+2)/2×+4 -2×2--4×+63))f' ( +8×+4×+8UX22.x✗ +=x -

=- (2×+4) ''(2×+4) }{2×2+8×+14 Rtx 2/D: SEMPREE0 -> ER(2×+4) 2+4×+7 tx CRESCENTE? > 0<N o✗ →: ☐'(4×+8×2×+4) (2×2+8×+14) )/ (uxtdf.ua?-I6xtI6 16×3-32×28×+16 ) -64×2)" (f -128×-112×-224-=× -=" ")( (2×+4)u+«+3*+12/8×+128 -9¥16*+6*1-64 -16¥ -12/8×-112×-224 -48×-96✗= so=" (2×+4)) "( zxtu }{ -2the R -D : 2-48×-96N -2 ( -20 ✗> ✗ > 0: no- - , FLESSI--un2- a• Ixy =t.,a.A. ..)(3)f- ( x2 -2,03 x ✗= -. )f-IRIR DERIVABILED E 2,0SU SU= ECONTINUA3×2f ' )( 2x× = - flaf-f )' )((c) +8+4b -= 6= =b- a 2 Fa? ' 4+72 1 ±3C 6 Cia2C -2C3C 0 26 ±= → == =- - 36| " ttx2 DX'2 tdi4 at1 ✗ =I+ ✗=+ =I× . - e , ,_o È| / "t ¥tti 'dt (1++2)dt c= + s= e_ +¢ 3,Fo) B-f- ((1) +2kf- 1§=o -1-

=- = 33 33 )/ ) 2.f ( (1)S u= ×× × --. ↓ ↓/( ) 4))) /f' (( 2-2×+1( '3- -2×2+8×1=× u =✗ ✗ ux ✗ =a ✗ -- -. }↓) )'( (3×2-12×+9)( 6×2+9×-43-6×2+9×-43 §✗= == ✗-3×2-12×+9 2 +3UX✗= -= ' '6×2+9×-4 )3-> ' (6×2+9×-4 )3-(3 ✗✗ 2- 3f' ✗+3( )b. UX✗ -=x =' '6×2+9×-4 )3- 3( 3- 9×2+24×-16✗ ✗¥+3 )ᵗD= -6×2+9×-4 0≠3- 6×2+9×-4 ≠ +96 -41O✗ -f- (1) 1-6+9-4=0= 1 S 41 -)1)( x2( -1-0 1 Ssxtu U 0x -- -1≠✗ 25-16--9D= 3 ≠= SI U✗ ✗-12 \2 ≠ 1✗D= in ≠ U≠✗ ✗ +-23Xluu - •=C. = _3l' Ò✗ - di→ 3- 9×2+24×-16 1✗ punto=✗ a)(cuspide +io- ,'Un 3✗ 2- so=- +=31-✗ 3- '9×2+24×-16→ 0✗ di3 1-✗un + 4- so punto✗== =3 flesso- -✗ U 0 Tg verticale3-→

9×2+24×-16 a✗ d)( • ++ ,l'3✗ -lui - = + A=Ut 3 Ò3- 9×2+24×-16✗ → ✗DELTEMA 24 2201 '.)f ( ×+21 × @= .. IRD= R2 (tlx× )@ E≥ A✗ o 0,0.Un fa )2. infinitiè iluigerarchia degli•+= o ◦=per→✗ . •✗A✗ →→ -- " "un a+l = +to •+× =' .✗ + •→ ORIZZONTALE0 ASlf = . 2. è×Un lui •++è ✗• OBUQUOm ASNO= ✗ =q →=. .◦0 ✗ INio✗ →☒→ ±f' )) 2. ' IR(( ltxè èè è2X + c-✗ tzx o= >✗ o>=x . 02-2)( O>✗ +✗ i i)( -0,5-2 >M × 0, -- -)( -2>×0,0m _ _ /:\1" ) (2×+2))f (( ' èè= +2xx 0>✗ + @m)(è 2+4×+2 0>✗ ZtfR-2 - -IRV'è 0> ✗ C- l lE2+4×+2 ±U -8 ±16 2✗ =×so - = -,, ,_2 UunET2<✗ V >✗ 2z +- -- I &FaF1)( KFiF1 -2 3,420,4~- - Il testo formattato con i tag HTML è il seguente:

9×2+24×-16 a✗ d)( • ++ ,l'3✗ -lui - = + A=Ut 3 Ò3- 9×2+24×-16✗ → ✗DELTEMA 24 2201 '.)f ( ×+21 × @= .. IRD= R2 (tlx× )@ E≥ A✗ o 0,0.Un fa )2. infinitiè iluigerarchia degli•+= o ◦=per→✗ . •✗A✗ →→ -- " "un a+l = +to •+× =' .✗ + •→ ORIZZONTALE0 ASlf = . 2. è×Un lui •++è ✗• OBUQUOm ASNO= ✗ =q →=. .◦0 ✗ INio✗ →☒→ ±f' )) 2. ' IR(( ltxè èè è2X + c-✗ tzx o= >✗ o>=x . 02-2)( O>✗ +✗ i i)( -0,5-2 >M × 0, -- -)( -2>×0,0m _ _ /:\1" ) (2×+2))f (( ' èè= +2xx 0>✗ + @m)(è 2+4×+2 0>✗ ZtfR-2 - -IRV'è 0> ✗ C- l lE2+4×+2 ±U -8 ±16 2✗ =×so - = -,, ,_2 UunET2<✗ V >✗ 2z +- -- I &FaF1)( KFiF1 -2 3,420,4~- -

-- -,FZ ( )Ztf E0,2 2 0,6+- - ~- -, // di DXcosi cosxtsinxCOSXSMX3 = + c✗ =+ ✗✗ --.f 'G { -1è)(f- =x 0le >×Sin 3 ✗)Kati ≤ O✗è (1 f- )luiCONTINUA o-: =sin 3O' ✗-✗ → KUn 0 =-0✗ O→ " 3-1l 3Xper sin ✗~ ~eo ×✗ → ¥ Kun K }' ==-o✗ → A)f- ( 2X 4S ✗x == - (f') a) )( (f Xo✗xo = ✗y • -- fu)f- ( 8- 2=6= 8u =-f' 7)( f'1 1(4) 2× 2= == -- -am U, U)( §%6 u -1= y =× →y -- ×DEL 04 22TEMA 12 '-3×1-+2FG )1 =. 4✗ - (4,1-0)a)(D: D=-1-0 io✗ u- - ,)3×1-+2 (✗ 3. + ≥×N >diO o≥ : le✗o -✗ leu o≥ >× ×- ≥ -3✗ ???) -al -3,0 } ◦.)(B N0o :