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CONTROL SYSTEM DESIGN
REVIEW OF CLASSICAL DESIGN TECHNIQUES
INTRODUCTION
The S/C attitude dynamics is non-linear but as first step we'll perform a linear analysis in a simplified configuration where we consider a single axis rotation.
If the S/C is required to have a large pointing accuracy (e.g. because it's got enormous solar panels) this attitude must be strictly defined and maintained against disturbance torques and passive stabilization is not sufficient, so we equip it with an active attitude control system.
S/C STRUCTURE
- Body of the S/C - contains all the payload instruments, must be very rigid as withstands residual forces.
- Flexible appendages - antennas, solar panels, booms built from light materials and easily bent.
We model the body as a rigid central body with moment of inertia J and the appendages as massless beams of length L bearing empty B.j carrying a tip mass m:
Tc -> control torque
Td -> disturbance torque
If we suppose to have n d.o.f. pendulums we obtain a one degree of freedom system with d1(t)
T = 1/2 J0 ḋ12 + 1/2 m l2 ḋ12 + 1/2 m(l ė1)2 = 1/2 (J0 + 2m e l) ė12
V = 0 (m like rigid case)
δWnc = δTc + δTd + δQd = δQd - virtual work due external and disturbance torque
Recalling that the Lagrange function L = T(θ, θ̇) - V(θ) we write the Lagrange equation:
d/dt ( ∂L/∂ḋ1 ) - ∂L/∂θ = Qθ => J0 ë = Tc + Td equation of motion in the time domain
LAPLACE DOMAIN AND TRANSFORM
Instead of working in the time domain we can work in the Laplace (frequency) domain.
DEF (LAPLACE TRANSFORM) → L{f(t)} = F(s) = ∫0∞ f(t) e-st dt
where s = σ + jω ∈ ℂ (complex variable) ω = frequency [rad/s]
So in our case we have:
Θ(s) = L{d(t)} and D(s) = L-1{Θ(s)}
PROPERTIES OF L
- L{a f(t) + b g(t)} = a F(s) + b G(s) → linearity - superposition
- L{ d/dtj f(t) } = s f(s) - f(0) → derivative
Properties of the Delta Function
δ(t) = 0 for t ≠ 0
∫-∞∞ δ(t) dt = 1 (unit area)
∫-∞∞ f(t) δ(t-t0) dt = f(t0) (sampling property)
δ(t-t0) = δ(t0) δ(t-t0)
It's possible to compute the system's response to any arbitrary input u(t) by using the impulse response h(t).
- We can decompose the given signal into a sum of elementary components and, by superposition, we conclude that the overall signal is the sum of the response to the elementary signals.
y(t) = ∫0∞ h(t-τ) u(τ) dτ → Convolution Integral
Let's suppose that the input signal for an LTI system is a short pulse p(t) and the corresponding output signal is h(t).
If the input is scaled to k0 p(t), then, by the scaling property of superposition, the output response will be k0 h(t).
If we delay the short pulse in time by τ, the input has
1)
G(s) = μ
│G│dB
0
│μ│κ→1
ω
∠G
0
μ→0
μ 1.
But we notice that to have good noise rejection we should have |L(jω)| > 1 for low ω