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Norme di un vettore
Le norme di un vettore possono essere espresse in diversi modi:
- Norma Euclidea: ||x||2 = sqrt(sum(|xi|2))
- Norma uno: ||x||1 = sum(|xi|)
- Norma infinito: ||x||∞ = max(|xi|)
Tutte e tre fanno parte di una famiglia generale di norme, definite come:
||x||p = (sum(|xi|p))1/p, dove p ≥ 1.
Da notare che quando p tende all'infinito, si ha:
||x||∞ = limp→∞ (sum(|xi|p))1/p = max(|xi|)
Quindi, per ogni componente si ha che |xi| ≤ ||x||∞.
Inoltre, si può dimostrare che:
1||x|| ≤ ||x|| ≤ ||x||n∞
E visto che limn→∞ ||x||n = ||x||∞, si ha:
||x||∞ = maxi=1≤i≤n |xi|
Per determinare quanto più grande potrebbe essere ||y|| in confronto a ||x||, si può scrivere:
||y|| / ||x|| = ||x||∞
Il fattore di espansione della norma è quindi:
||M|| = sup(||x||∞ / ||x||), dove x ≠ 0
Il massimo fattore di espansione della norma è dato dalla formula:
||M|| = max y ||Mx|| / ||x|| = max y ||M|| ||x|| / ||x|| = max y ||M||
dove y è un vettore unitario.
Per due matrici A e B, si ha:
||A + B|| = max (A + B)x = max (A + B)x / ||x|| = max (A + B)x / ||x|| = max (A + B)
Un'altra proprietà importante è:
||Mx|| / ||x|| ≤ ||M||
Abbiamo visto che:
||x - x̂|| = ||A|| ||r||
Per la precisione, x̂ è chiamato errore assoluto. Spesso è più utile usare l'errore relativo:
||x - x̂|| / ||x||
che fornisce l'errore come una percentuale della norma della risposta.
esatta.8Visto che b = Ax ||A||1||b|| ||Ax|| ≤ ||A|| × ||x|| ≤= e ||x|| ||b||||A|| ||A||1 −1||x − × ≤ ||x − × ≤ ||A || ||r|| ×=⇒ x̂|| x̂||||x|| ||b|| ||b||||r||||x − x̂|| −1≤ ||A|| ||A ||=⇒ ||x|| ||b||||r|| ||b− b̂||− −Possiamo scrivere r = b Ax̂ = b b̂ e quindi = è l’errore relativo nel termine noto.||b|| ||b||−1||A|| ||A || è il gattore di espansione dell’errore relativo, si chiama numero di condizionamento dellamatrice.8 Formule per Norme di Matrici8.1 Teorema per la norma infinitom×n∈Consideriamo A . AlloraR nX |A |||A|| = max∞ ij1≤i≤m j=1cioè la massima somma delle righe in valore assolutoDIM:||Ax|| ||Ax||= max .∞ ∞||x||∞=1n∈ ||x|| |x | ≤Sia x , = 1 =⇒ 1∀jR ∞ j nX||Ax|| A x(Ax) = max= max∞ ij ji 1≤i≤m1≤i≤m j=1 nn XX |A ||A | |x | ≤≤ maxmax ij j
ij1≤i≤m1≤i≤m j=1 j=1||A|| ||Ax|| ≥ ||Aa|| ∀a ∈ ||a||= max = 1.R∞ ∞ ∞ ∞||x||∞=1
Consideriamo un a speciale; sia k l’indice di una rigan nX X|A | |A |= maxkj ij1≤i≤mj=1 j=1
Definiamo:
+1 se A > 0kj
a := sgn(A ) = 0 se A = 0j kj kj
−1 se A < 0 kj
||a||Notiamo che = 1. Quindi∞ ||A|| ≥ ||Aa|| ≥= max (Aa) (Aa)∞ ∞ i k1≤i≤mn nX X= A a = A sgn(A )kj j kj kjj=1 j=1n nX X|A | |A |= = maxkj ij1≤i≤mj=1 j=1
Abbiamo dimostrato che n nX X|A | ≤ ||A|| ≤ |Amax max∞ij ij1≤i≤m 1≤i≤mj=1 j=1e quindi nX||A|| |A |= max∞ ij1≤i≤m j=1
8.2 Teorema per la norma unom×n∈Consideriamo A . AlloraR mXt||A|| ||A || |A |= = max∞1 ij1≤j≤n i=1cioè, la massima somma delle colonne in valore assoluto.
8.3 Teorema: Dualità n∈Abbiamo le seguenti formule duali per le norme di un vettore x Rt||x|| = max y x1 ||y|| =1∞ t||x|| = max y
x2 ||y|| = 12 t||x|| = max y x∞ ||y|| = 11
DIM: # NORMA 1
n∈ ||y||
Sia y tc = 1R ∞ n n nX X Xt ≤ |y | × |x | ≤ × |x | ||x||y x = y x 1 =i i i i i 1i=1 i=1 i=1t
Quindi max y x.||y|| = 1∞ t t n≥ ∈ ||a||
Dall’altra parte max y x a x per qualsiasi candidato a = 1.R ∞||y|| = 1∞n∈ ||a||
Sia a dove a := sgn(x ) = 1.R ∞i i
Quindi n nX Xt t≥ |x | ||x||max y x a x = sgn(x )x = =i i i 1||y|| = 1∞ i=1 i=1
e abbiamo dimostrato che t||x|| ≤ ≤ ||x||max y x1 1||y|| = 1∞
10DIM: # PER NORMA 1 DI UNA MATRICE
t||A|| ||A ||
Useremo le formule di dualità per dimostrare che = ∞
1 t||A|| ||Ax||= max = max max y (Ax)1 1||x|| ||x|| ||y||=1 = 1 = 1∞
1 1 t t= max max y (Ax)||x|| ||y||=1 = 1∞
1 t t= max max x (A y)||x|| ||y||=1 = 1∞
1 t t= max max x (A y)||y|| ||x||=1 = 1∞
1t t||A ||A ||= max y|| =∞ ∞||y|| = 1∞
8.4 Teorema: Norma 2 du una matricem×n∈
Sia A . AlloraR p t||A|| ρ(A A)=2n×n∈dove,
Per una matrice M, il raggio spettrale |λ|ρ(M) è dato da max1≤i≤n|λi|.
DIM: n×n ∈
Consideriamo prima il caso più semplice, A diagonale
R||A|| = max22||x|| = 1/2
pp t t t(Ax) (Ax) = maxx(A A)x = max||x||1/2||x||2 = 1/2
( )
nX 2 2= maxA xii||x|| = 1/2 i=1
≥
Interpretazione: sia λ := x0i i v nuXu 2
max λ A media pesata
it iinP λ = 1
ii=1 i=1
Quindi v nuXu 2 |A |max λ A = maxiiit iinP 1≤i≤n
λ = 1
ii=1 i=1
Allora, per una matrice diagonale ||A|| = |A| = max2ii 1≤i≤n
DIM: # CASO GENERALE
Def -1n×n t t t∈P è ortogonale se P = PT, cioè P PT = PT P = I. Sono matrici che rappresentano rotazioni
R n∈ o riflessioni; Ha la proprietà speciale che per x ∈ R2
t t t t||P ||x|| = (P x) (P x) = x (P PT)x = x x = 1.
p t||A|| ||Ax|| = max = max (Ax) (Ax)
2 2||x|| ||x||=1 = 1/2
p t tx (A A)x = max||x|| = 1/2
t tMa M := A A è simmetrica; M = P DP dove P è ortogonale e D è la matrice diagonale
degli autovalori.
$$||A|| = \max_{x} \left(\frac{P^T D P}{||x||}\right) = \max_{(P x)} \left(\frac{D(P x)^2}{||x||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2} \max_{y} \left(\frac{Dy^T P^T P y}{||y||}\right) = \frac{1}{2}
saràR t t t t tx Ax = x (P DP )x = (P x) D(P x) = y Dy
[ ] λ 0 0 ... 0 y1 10 λ 0 ... 0 y n2 2
[ ] Xt 2
[ ] * * ∀ ∈ ≠ ⇔ ≤ ≥y ... y ...x Ax = = λ y > 0 y = 0 λ > 0 1 i n1 n i i
[ ] [ ] i[ ] [ ] * *... i=1
[ ] [ ] 0 ... 0 0 λ yn novvero A è definita positiva sse A simmetrica e i suoi autovalori sono tutti positivi.
9.1 Teorema: Choleskin×n n×n∈ ∈La matrice A è definita positiva sse esiste una matrice L triangolare inferiore,R Rnon-singolare tc t×A = L LLa matrice L si chiama fattore di Choleski di A.DIM con esempio... 129.1.1 Lemma n×n n+1×n+1∈ ∈La sottomatrice principale A di una matrice A definita positiva è anch’essaR R1definita positiva. A c1 −1n+1×n+1 t∈ −Se A = è definita positiva, allora a c (A ) > 0.R n+1,n+1 1tc an+1,n+1 ...10 Interpolazione
Il problema di interpolazione polinomiale è il seguente: Nodi: x₀, x₁, ..., xₙ (n distinti) Valori: y₀, y₁, ..., yₙ Trovare un polinomio p(x) = a₀ + a₁x + a₂x² + ... + aₙxⁿ che passi per tutti i nodi dati.