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Poniamo

[math]\\logx=t[/math]

ed otteniamo una "normale" equazione di secondo grado in

[math]t[/math]

[math]2t^2-19t-10=0[/math]

che risolta dà :

[math]t_1=10[/math]

[math]t_2=-1/2[/math]

[math]t=\\logx[/math]

e quindi adesso dobbiamo risolvere l'equazione logaritmica:

[math]\\logx=10[/math]

, da cui:

[math]x=10^{10}[/math]

(se siamo in base 10)

e anche l'equazione:

[math]\\logx=-1/2[/math]

, da cui :

[math]x=10^{-1/2}=1/\sqrt{10}[/math]

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Equazioni esponenziali e logaritmiche: 2(log^2)x-19logx-10=0

Poniamo logx=t ed otteniamo una "normale" equazione di secondo grado in t : 2t^2-19t-10=0 che risolta dà : t_1=10 t_2=-1/2 . ma t=logx e quindi adesso dobbiamo risolvere l'equazione logaritmica: logx=10 , da cui: x=10^

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