K
fruce-frus
Mal = Lidd
con Liod=
Li
K RT. (p.
K-1
-1) = 283709, 6125 Jike
K-1
Li * = 466989, 424
Nod = (0,60752889
Pa = Gli (296 944,362.
29
# #TD_ 17/02/2023 ##
De=013m Aza G.F. subsonico
But m = 1,32
As = 17,7 J/rgk [G= 5,060 140/S; T = 543,6K; M = 0,841; D = 10,91]
M = C C = 203,309 m/s
SKAT
G= &A= P C D ($060ng/s)
RTL
C
G = P C TD
4
RT
AS = K Rei T-RG (1) () = AS/KR_RM
K-1
M =
!
KRT
08413
CONDOTTO ADIABATICO N=23.
P = 3,2360 M = 0414
2T1 = 600 K
D = G (T R)
VE
TUD? ?
4
Tº = TL + 620,5675. K
T = T2/4+ K= CZ
2 KRTI
T = T expl 1) = (543,6K)
M-1
Tôi T o
C = (T0-7 ) 24p
= 0,109058 m = (10,91 an
P2 / (2
2 P . = P ( 12 ) = 2, 14,95bon
= 333,295798,
ay
#TC_17/05/2023 # #
2-3 ISOTERMA
REVERSIBILE
#
{P = 1box
T = 290 K
~ P2 = 5Lor
7=985
REDM
ISENT
4-2
3-4 TURBINA → y = 0.85
Im = 1,326 ; P = 8,397b0z; AS23 = 53-52 = - 0148917; L = [L = 72,82 KJ ]
KK/
(Li). = c(T2 T ) = 170124 065 5/16
T
is
This = T1 (459,308 K
T2 = T3
12 Li = Lied = 200 143, 196 J/kg •
T = L; + T = 439, 1991 = T3
1
nyc
=
K m-1
→m=
K-L
m
D
m
12
P3
P
- K
K-L
= 1,3257
326
K-I
P
P3
→P3 = 8,379 boz,
T3
15=
Rem
23 = -148,9115 1 =
01489 KJ
1-2) Li = c(T2-T ) = 200 145 J/Kg
31) (4 CKCT-T2) - Ai = -1/ JIKO EL = (72,84 KJ/Kg
2-3) Isotama
Li= RT en (31) = 72844J/kg
## TERMOD - 23/09/2019
R=237 1 J/1 K=1 4
Sap=
SCP = K R = 1004, as
+ R = 717,75
| cv = 1/ +
AS12 = 49, 48 1.
My = Li_Lw
1-2 IRREV LW 70 compressione Adudcatica, politopice A
se JEC = Q
Li-Lw= m K-
m-1
K
1
SP = Ita
| T = 2881
Li
23 = 66 17114 ; Tmax = 413,9 K
Tas = di- vdp
dS = CRT _ / dy = cpdt -
CpdT
T
AS = colu(It) - Ren (P )
= 49,48 3/1gKk
Q
m
( Lizz - You" = m RT (123)
m-1
REV
m = ? ß m =
23
##
12
LitQez Aiza(32)
31 i sentropice m
AD. REV.
31 = EUL. =
m 1 DEC = Q
|
K
2ym K - Kyk = mk - m
2y mk -m k +mm = uy
nyk
Myk-K +1
3=
CICL TERMODINAMICO
1-2 Adudo. fazeu 2y = 0,302
@ B3 = 2,01
2-3 Refrig-Rev 12 = 4 8 S = S3
31 Adiab.
P3 = B 3 P = 3,618 bos
As x = Q> cp It - Reu B = []
Cu
13 P3
1 ->
1 ->
T2
P1
R dp
1
K RT
K-1
com
Liz3 = 66 176 J/ig = 66,17 K3/kp
(Li) out
k
= 1,553403
-S
P = 1 · P =
T2= Ti. (Po
P
KRT2 ( m
K-1
EUGER (2
MECC
-1
=
(m-1) emß = en (.m_) mm = enß
ma
3
PL
EVLER 1
TERU
-luc + luß
Lidt 31
• maz
$=53 3
2,01 60 = 2,01·10 Pa
= 128,5 K
iP
m-1
m = 369,323 K
• [Cp/T3-T ) +1=1 RT
KC RT = CP(T3-T ).
K-1
RT2
P
Twox
; T3 = T (Br) Ace (412,9)
Pi
c=1,126087463
+ 1
m=e1,25318
K RTB ((P4)* - 1 ] = 123 494,58 5|fe = (1,28,3 kJ/kg)
# # TERMOD: 06/11/2019
##
d = 20,1 cm = 0,201 m; Pa = 1 1602; e = x = 1m Ti = 350K.
; Tf = 436 K ; Ax = 24,56
P= 0,15 kW Fa 20s; Pf = 1, 1
J Pi = Pa
= 14ter
Per epl Pistone [pf = Pa= 1,160c
Vi= Ax = red . Xo = 0,031731m
·m = P.V =
RT:
0,034736kg A=09317311
IPTO LAG TERMICO
3000 J
[+ = AU=com (Tf-Ti)
[" = - Spav=p_(ve-vi) =_P_Tq A x
I = [ + [ = mcu (TP-Ti)
T&=
civ p? Axi -mcvrti -L'
R
- PA - CUPEA
PRA (Ax + xi) = 435,92 = 435,9 K
Rm
Noon Sistema Pé' > Pa
Pi = 1, 160c
Ti = 435,91
'Pf = Pe
Te• ?
=
L' - Pe Tud 4x = CU PP 1 A x + Cv PP Xxi - mcrti
4
R -(-3000)
R
+2999,9076.
30000924 = (24, 55 m
M = 0,0347 36 19
x = x i di prime = 1m
Riporto pistone a & oumentando la
TimTema fimdi Tf' = ?
• Tf = 473,98
[= AU=mcu (Te-Ti)
FORTE ADX = gncu TR - o cuti
Axf
Te'= - - CUT: / (RAE - CV) =
PiT || Pe
X
Petfi
P
X
> Te = Peve = Perd . (Ax + xi) *
4Rm
Pe
I=-Sp dv=p (V; - vp) = + P AAX com B = MRTR - MRTÉ
m
Vf
NO
NO
ATTIRITO
Volume diminuisc AV CO
e x = xf = xi +Ax = 1,2456 mu
ISOLATO
TERMICIM
A xf
Toof. Adubotica - Rev Iscentropice : quosi-statica = ideale
K
Pi Vi's Pe Vok
=
> Pf = P = Pi (vir ) K = P (xi) ^ = 149 597 P
G.P. Peve Tf = (475,98K
MR.
# # TERMOD_ 18/01/2019 # #
Pa = Abor COMPRESSIONE
IN
T = 2901 TURBOC
ARIA OM CICLO TD
m = 1,451
T3=T =290K REFRIG. IDEALE
Poi
RISCALD. ISOBAR TS
P = 5,36ar | COMPRESSIONE ISENTROP. Pl. = 32,05 boy ESPAND. ADIAB 1 =9,85
Cod
P
Q23 = 214,8 1 5/150 ; T3 = 622,8 k; Recipus = 39,99 kJ/kg ; Lc = -60,93 kJ/kg fins a
Espansione
256 -
REFRIG
T
K = 4 4 ; R = 2 87,1 µ JHCK SCP= I R = 1004, 85 sligk
K-1
CU = AR = 717,75 J/K K
T3=290k
T = T P2
Pj
m
m = 500,826 K
I PTD EULER. TERMIO
Ki + Qe = si + Fém
Q = Cp (T3 - T ) = (-211,849 15/19
Qe
2 = ([idtt) is Tros! 5-6 com
5-6is Tof. ISENTROPICA
[PG = PG is = P = 1ton
P5 = P4 = 32,0360
I = (Ps
Tois
16.=
T
is
R 56 = ? Litt = Liett. +. Lw - R..
4
Pois
2
m
T5=? ¡SOBARA P4=P3 poidic Aue gas perfetto PV = RT
3-4 iszutagprica Th= T3 (24) 2 ian 2-3 isuntiopica P3. = P2 (12) 1-1 = 0,35687464
K
T4 = 816, 2036 K
3
& DIAB
T54-T6nd6 =TS-76
flList - e =-Ai = Cp (T5-T6) ; 1= Is - T6
Riot = - Dis =
TS-T6 is
34
5
6is
P
T615 = T6-13 + T5
Zod
# # TERMOD_ 07/11/2018 # #
<=6000 N/m
d = 0,201m = l = 1,5m (molle trazione) ^x=
P = 1601
Ta = 310K
-
4 = Td = 0,0317309 m
4
Vi = A. Xi=00 4759635m. .
P.A
.FK
Ti = 330K
PV=MRT
P = ? EQL, PISTINE
L
Mi
POA
- Pi Vi = 0,06020 1
RTi
12 = 25 12 = 2^x
0,105m Pe= ? LPISTONS = ? AS = ?
ARIA g.P.
1 SDR =' dV>o ho Q>0 (Ie fluido comple Buro)
edx->dV 0 DESTRA X
FKE
Q = ? Log. Temico
L + Q = m AU = mc (Tf-Ti) = -6057,36
[VR = Axe = 0,040932861 ; T = R V = 189,311
Tf Pf Vf
K
MR
Pi
www
Ti
Q = ([+Q) - [ = -6723 5
J
TO Poiché Ve-Vi
Qe= -Q
e=xi
Xox!
Xo<xi
x2
A Pi>Pe -> Scalpo verso positivo Fx (simistra) per equilibrone
-Fi + FK + Fest = Q ; -P A + K (xi-x0) + PA = Ø Pi = K (x -Xo) + Pe
Xo = Xi - Ax = 1,395 Pi = 119.854, 4636 Pascal = 1,1985 45 60 > Pa
LA FORZA ELASTICA É POS SE VERSO SINISTRA A
D
xp = x = 2^x = 1,29m -> x£ < xo. cioè la malle e' im compressime
•Losaic FK mal suo vauso positivo os! dipende tuTTO X X
Ff
=- A(XR -xi) — 13 [(XR -x) – (x - x0) ] = +666 J
- k
2
9
Pe Pa
Pe > W
7
Ta
TR
origine
SDR
Tols = dQQ + d you
Lze Mack
Vf
L-4 0 = - pdv = - + Pe + K (x-xo) dV com dV= dx A e {V =XiA
1/2 Zvi=xi
=X&A
NO AT
"Fest - Ff÷ F +Fest = Q; P £ A÷K(X1 - x0) + P A = 10
PR = K (x -x ) + R| = 80145,536376= 6801 4553637 bon
Ta
l'=e-se
xf
xf-x
L = - ^*^* e A dx - 1 (x - x0) dx =-P_A[x -x ] - [ ^ K (x-xo) d (x-x )
Pa
Xi
x - xo
XB-x.= 0,2
xi - xo 29199
+
As = M (la T £. cp + Raive.)
Vi
Ti
Ase = Qe/T =...
' As? Tas = dº + pola.com {=MR
AL
CPAT
Pdv
RdV
Binte ds = cor. Lov = M(CRAT +Rav)
+