Esercizi e prove esame svolte di Scienza delle costruzioni

D

PE 2 P UPY

-P 2 Plz

P(z PIE

+ + +

+

+ -

-

= PE PLZ

+

=

- 2

2

0[26-L

DOMINIO P

aPL

-P -

W P P

44

PL/2 "PL

Li ↑

↑

4 PL f

Y2 42

L L L z

,

,

1 &

I I > I

N 0

= -

P P 2)

2P

P P( pz

P

+ +

T +

= -

- - - = 2)

2)( +

P(4) 2)

2) P(((

2)

P(3) 2) P(

2P)(3)

Pz +

M + +

+

+ + +

+ - - =

= 2 DE

Pt

&

2P( 3P 6P(2

P PLz

2P(z

P(z Pz P1z Plz

P(z

+ +

+

+

+ +

+ =

= - -

- N

PY2

PL/2 T

e PE M

YIPL

.

esercizio O

M PL2

= P R

p(2

Ne

PL

2M < i x

YA 12)

4

↑ YB

↑ 4y

5

Lo

XA ,

> V

- ,

-

x

- Tyc L

~ yoH

-

XD

Ex

1 XA 0

Xc =

: -

. 0

-YA

2 YAtYB-PL

EY 0

Yc =

: =

. 2

-

- PL2

~ IPL

2 PL PL

PL2

[M(c) YBV

424

PR -YA2L-YpL

.

3 YB

t

2 0 <

=

- =

- -

-

: -

4

. IX Xc-XD 0

: = P

P

Yc-YD-PL

ZY yp yp

.

5 0

= =>

=

c =

: -

-

yc

Yc

EM(D) 0

6 0 -

= =

=

.

7 EX Xp 0

: =

.

3 EY +

Yp YG

Ye

+

: 0

YG

>

0 =

=

. PC

-2PL2

9 EM(G) YEL-Yp2L

. PL

BE

+ ,

= - =

PL

PL

2PL2 PL &

↓

↓ <Pi

S

S ↳ PPL TPL

PI 25 E6

5 3

zz It

zu

I . c 1 -1

1 /

<42

Dominio 12 Y2

DOMINIO

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DOMINIO

, 2PL2

2p 4 PL

2P ↑ ↑

↑

(pz Ec S Lpc

-

V /2 4/2 2

CEO 11 >

I I

{

N 0

= {i

2P N 0

=

0

+ = PL2 PR

-2 PE

M + =

= - a

= - 2 PL2

M Pl

PC P12

PLz +

+

= + =

- -

0125

Dominio DOMINIO L

[24 =

Il

0 PL

PL

PL 2PL2

2PL2 PL

PL ↓

↓ ↑

↑

↓

I S b

Es f

S ↳ >

-

PPL

PI

Z

L/2 2/2 L T

e

I 12,

( / 5

3

I L

I 2

1

,

E

N N 0

=

0

= P

P

P PL

T + +

T =

=

0 -

= PR

2 P(2 PL(2)

M

PL2 PLZ

PL(L

2) 2)

M -2 P12 2) PLZ

PL/L = +

+ +

+

+

= + -

+ -

-

- +

+ PIz

---P12

PC PL2

PL2 PE

-

P1z

+ =

+ 0 -

=

= = =

-

Dominio 0426LL PL

PL

2PL2 ↓

↓ ↑ Ec

S ↳

-

APL TPL

PI2

/2 L E

1

,

,

{

N 0

= P PL

P P

T + 0

+ =

= -

-

-2 PL2 P((2L

P12 2)

M PLz

PL/

2)

PL(3L 2)

+ +

+

+

+ + =

= -

-

+ P

2P -*

-2PK -

3 P 2

-

+ + = -

-

DOMINIO 27 L

:

0 PL

PL PL

2PL2 ↓

↓ ↑

S r

↳

S >

PPL TPL

PI

42 L 2

42 1

L

L

1 / I

I

, , ,

N 0

= PL P PL P

T + 0

+

-

= =

- P/E

2P2 = P(((

P)

2)

P

M 2)

P(E 2) PL

2)

+

+ 2+

+ +

+ +

= =

-

-

- - R

P 2 R e

Plt-Pl

EPL

PR P PL

E P(z

PIz

2 plz

+ + +

+ + =

=

= -

- -

-

- N

- T

I n M

-

D

esercizio N

N YYG

W

~

~ pYD

Y

NUB ↑Ve

↑

XA D

-XC a

,

L by

< in Lyd

~ MA

EX PL

Xc

1 XA -XA

= 0

: =

- -

. P

-PL

YB-Yc

ZY

2 YB =

>

: = 0

. -

PL

Ma

M(A)

.

3 y(2)

YB)

+

: - - 2 PL

IX

4 Xc-XD XD

: x

= 0 = = -

>

. *

YP

Yc-YD

. PL P

ZY

5 + 0

=

: ? =

-

- 2

P

ZM(

6

. YDL + 0

- =

: 2 PL

PL

EX

7 Xp Xp -

+ -

0 =

: =

.

8 YG-PL

+

Yot Ye

ZY 0

=

:

. Pl

9 EMid) 2ygl

Yel O

+ =

:

.

PROVE ESAME 2019/2020

YA Y W

i YB

X B 4 PL

IPL

XA COS/4150)

XB

- + =

- >

- (1150)

___; Sen

1

↓

↓ EPL

MA YB -- I 2 PL

ERR

U2PLSen/U5y) COS(450)

2PL =

< ↑ YG

EX PL

XA

XA-XB

1 0

: = - =

. 2PL

IY

2 YA-YB-PL YA

0

= > -

: =

. PL2 P

MA-YBL Ma

.

3 [M(a) > =

= 0

: - -

I

P

EX 2P

4 +

XB

: 0

= PL

: >

- XB =

YG-PL

IY

.

5 YB + 3PL

-O

: YB

- -

=

PL P Pl

YGE-2PLE

6 EM(B) YGE YE 4

+ +

·

- >

: = -

.

per YP

5 23

p

D

-PL Spal ,

PL , ,

>

- __ P

PL 21x

-2 2

I I . ne4

2PL < -

425

↑ PL

4

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< W W

ï D

↑

D

5 ↑PL

PL ↑F

Es

PL

> PL

C

-Esoft &

> -

- ↓ p

,

2PL

2PL 3PL

V

V 2 L 2

I > I I >

E E

PL

N PL

N =

= - - PL

2P

2 PL 3PL

P2

T T +

+

= =

= P

PE

DLE Pl(y 2PK

Pl

5 P(z 3P)

M P 2) 2 Plz

E

2012 M 2P(( 2) +

+ =

= -

= - =

- -

-

-

I

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DominIO 0 W W

D

↳

W W

D

↳ D

PLY3PL PL

-

2

N P

>

&

D PL

- Es

2 1

> .

& -La

PL ⑭

PL

3PLy -2

>

-

2PL -

Z

4/2

V L I 1

I I

>

L

2Ph ~

↑ 4PL =

E P PL

N 2 P ↑

+

= UPL

PL-PL-2PL

= N

= = = -

-

PL

4PL

PL

2PL

T =

+ -

= P

- 2PL

P

T = =

-

- -

PL2 4PLz

&P 2P(3 2)

M P( 2) 2

2 PL3

+ Pl

-P

+ =

+ -

M

+ Plz

PLZ

= Di

- PL

+ +

- = - 2

- - = -

D4

⑤P PL2

3P2 Plz

2 P1z 4 P 12

+ +

= -

-

- -

PL P(z

+

=

- 012514/2

Dominio

W W

D

↳ D

-PL

2 P

1 . E

p 4PL

N

2PL = =

~

V P

P 2P

T

2PL + 0

= =

-

-

< 2 PL 3 2

d P PL(Y2

M PL/L/2 2)

-P 2 Pl

+ 2 PL2

+

+ +

+

= - - - - Z

P2

T -P

PE

EPR 3PY PR 2 PLz

PLz

-PLz +

+ +

N = -

- - -

ro

a ④ N

PPL I Pi

L M

·

④ O

T

2PL O PL

IPL P

y EX PL

P) -ZPL

1

Xcc +

-Xc + 0

= >

: XD =

.

FMD

XpL'P x =PL

, 2 IY

x x Ye-PL-Yc

↑ 0

: Ye

=

1 - =

. ?

YD PL

~ P

. P XcL

M(E)

3 yc

+

+ 0

=

: -

- =

c

Z I

U EX Xc-XD IPL

0

= x

: > =

. -

YeY -

PL

. +Yc

5 PL

ZY Yo + Sp

0

=

: - =

PL ·

> 4 cl -PL

Mp PLE

MD

EMp

6 + 0

: = I

>

. 2

pp di P

20 -2pP22

>

-

p -

↓ 22 23 zHx

1

I ,

>

I

-PL a

2 N

, =

↑

f

P 54 -

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DOMINIO

DOMINIO 0222142

OPE L DOMINIO

,

N

N ↑

↑ M

T M -

in

4 - PL

>

E

N { I

2 PL

N N

P

= =

- - PL Z

42

T = - , >

I

PL

T =

o L L

-

PLz M

M P(z

=

=

-

↑

PLX 4 a

P P PL

> > -

- {i PL-PL

N -IPL

= =

- P

P b)

+ =

= - -

DOMINIO 01ZH L

- P PLz

2)

M 3P(((

+

= - -

P R PC

3

* P(2

P(2 P(z

P(z

+ +

= -

= -

↑ - 4

.

Pz'PL

↓ E PL-PL

N -2 PL

42

42 Es = =

-

, , L P

=P p2

P Pz

T + =

= -

-

- - Pe

a 2)

PL)t

P(

-P( 2)

M + +

= + -

-

PL

> 2 DE PLZ

P

P

= &PLE

P Pl2 PIE

+ + +

=

- -

- 2

N T

O P

⑦

P O PL

3

2PL

po +

p

EPL2

↑

①

PC O M

+ PE

2018/2019 VD

~ PL

2X XB

1 XA

XA XB =

·

> : =

0 -

=

-

-

.

P x Ye ↑IY

↓ YA-YB

2

.

E YA PL

V YB

· 2

O

: = =

=

Xe

> PL2

Ma

.

3 &M(a) Ma-YBL YBL 2

YE 0

= =

=

:

=

a PL

EX Xe

4 XB XE

XB

YAPrMA . > 0 > =

:

- =

= -

-

YB-P)

↑ IV

. -VE-PL

XB 5 Ye

XA Y 0

< 0

= =

>

> :

G

N

I

↓ PL2

YB L

2 PL2

4 [M(E) 2PL

PL MG 4 YBL YB

XB

6 + t

: 0 · =

=

- -

.

> 2 2 PL

PL

. IX XE XE

+ = =

> 0 >

: -

-

7 IY

.

8 -YG

Ye

YG + 0 0

: = = PL2

Ma

VEM(G) MG XEL

Xel

9 >

. 0 = = -

=

: -

VD

~ 24

22

I

P I

, - I

PL

↓ >

L -

I I

-Es

PL

E

IPh N PL 25

2

↓

↑ PLE

r2 12's V

I

PL

-

PPL PL2

-

PL > -

TV

Dominio OLZ2L 0123142

DOMINIO Dominio

12 L

0 , -

-M

4

IPh aTwMN

↑ PLE -

r2 I P IPh

↓ z

PPL un PLE

I 2

E

Z N PL

L

0

=

I I -

-

-2 PL