Esercizio Sismica

Provetta Sismica

Materiali

CLS C30/35

f_ck = 30 MPa

R_ck = 35 MPa

f_cd = α_cc f_cm / γ_c = 0.85 × 30 / 1.5 = 17 MPa

Acciaio B450C

f_yk = 450 MPa

f_yd = f_yk / γ_s = 450 / 1.15 = 391.30 MPa

Analisi dei Carichi

Interpiano

• h = 5 / 25 = 1 / 5 → 0.20 m → scelgo un solaio (20 + 4)
• g_k = 2.86 kN/m²
• g_kz = 2.20 kN/m²

[Travetto, Cappa CLS, Pignatta, l = 50 cm]

• Piastrelle: s [m] = 0.040, ρ [kN/m³] = 22, Carico [kN] = 0.22
• Massetto: 0.040, 16, 0.64
• Polistirene: 0.035, 0.5, 0.02
• Massetto: 0.060, 18, 1.08
• Intonaco: 0.015, 16, 0.24

g_{k2, biom} = 1.20 kN/m² [tramezza]

g_{k2, TOT} = g_k2 + g_{k2, biom} = 3.40 kN/m²

g_{k2, TAMP} = 3.63 kN/m²

• s [m] kN/m³ carico [kN/m²]

• Blocco 0.30 10 3.00

• Isolamento 0.10 0.3 0.03

• Intonaco 0.03 20 0.60

q_k = 2.00 kN/m² [edificio residenziale cat. A]

• COPERTURA
  • g_k1 = 2.86 kN/m²
  • g_k2 = 2.20 kN/m²
  • q_k = 0.50 kN/m² [solo manutenzione cat. H4]

• CARICO NEVE (NTC08 3.4)
  • q_f = μ_i ⋅ q_sk C_E C_t

ZONA I ALPINA (a_s < 200 m) ⇒ q_sk = 1.50 kN/m²

C_E = 1.0 (cat. t2)

C_t = 1.0

μ_i = 0.8 (0° ≤ α ≤ 30°)

q_f = 0.8 ⋅ 1.50 ⋅ 1.0 ⋅ 1.0 = 1.20 kN/m²

A_s = \(\frac{M_{Rd} \cdot 10^6}{0.8 \cdot d \cdot f_{yd}}\) = \(\frac{644.29 \cdot 10^6}{0.8 \cdot 380 \cdot 391.3}\)

= 4814.36 mm²

d = 380 mm

d' = 20 mm

AREA COMMERCIALE

A_s = 4926 mm²

ρ = \(\frac{A_s}{b \cdot d}\) = \(\frac{4926}{400 \cdot 400}\)

= 0.03079

1% < ρ = 0.03079 < 4%

ok!!! VERIFICATO (f.4.6.2.2)

PESI SISMICI

EFFETTI AZIONE SISMICA → G₁ + G_z + ∑_j Ψ_2j Q_{k j}

(3.2.4)

PIANO 1

Solaio

w_sl = g_k1 + g_k2,so + ψ_2H q_k

= (2.86 + 1.57) + 3.40 + 0.3 · 2.00

= 8.43 kN/m²

A_z = 25 · 14 = 350 m²

W_sl = w_sl A_z = 8.43 · 350

= 2950.50 kN

Tamponature → g_kE,TAMPO = 3.63 kN/m²

INCIDENZA = 0.75 \[g_k2,TAMPO (h_interp - h_cordo)\]

= 0.75 \[3.63 (3.50 - 0.40)\]

= 8.44 kN/m

W_TAMPO = I · perimetro

= 8.44 (2 · 25 + 2 · 14)

= 658.30 kN

Verifica Torsionale

_{k = 3 ^EI/hINF}

h_INF = 10.5 m

Incastro

Setto A

k_x = 3 ^I_x/_hINF³ = 3 · 0.03²/10.5³ = 0.00008

k_y = 3 ^I_x/_{E · hINF³} = 3 · 7.20/10.5³ = 0.001866

Setto B

k_x = 3 ^I_z/_hINF³ = 3 · 4.1667/10.5³ = 0.001080

k_y = 3 ^I_x/_hINF³ = 3 · 0.0267/10.5³ = 0.000074

x_K = ^{∑k_yi · x_i}/_∑kyi = 12.50 m

y_K = ^{∑k_xi · y_i}/_∑kxi = 0.10 m