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MICROMECHANICS
Toughness: capability to stop propagation of a crack. It is related to energy.
Strength: maximum allowable stress.
Bone: hydroxyapatite + collagen (like rubber + rice).
Microstome of composite/bouvrage materials. Different orders of magnitude for example between tension and compression, parallel and orthogonal direction, relative sliding between layers under tension; buckling failure mechanism under compression.
TENSOR ANALYSIS
ith tensor (on bold letter) on indicio notation vi (i-th component of the vector)
Displacement: xi, ui = a component Cartesian coordinates x = [u1 u2 u3]
A·B = ATB = AiB1 + A2B2 + A3B3 = AiBi
ΔAB
c = j i k A1 A2 A3 B1 B2 B3
No ⇒ Nij metric
P3x1 = N3x3V3x1
N = Nijuiuk
N3 = Ni Nj N2
Unit second order tensor I = δij Kronecker delta I = 1 (i = j), I = 0 (i ≠ j)
Nij δiκ = Nii + N1δ1κ + N2δ1κ + N3δ1κ + N2δ2κ + N3δ2κ + N3δ3κ + N3δ31 + N3δ32 + N3δ3κ + N3δ37 + N3δ3 + N3δ33
Cijak (stress), Ekm strain
σij = CijakEkm
- 9 equations in total
- 6 linear independent equations
Continuum...
All physical points are occupied by solid matter. We are neglecting interspace between molecules and atoms, even within crystalline material.
For each point (characterized by the x vector) we can define a displacement vector.
We can define Et that is a tensor and a field E(x). Cp field
We can define the stress g(x) that is a calling tensor. The body is not floating, it is fixed.
- Δ displacement
- Pi
- σ linear independent equation of the second order tensor Et
∇E, σi unknown fields → 15 equations needed
Body forces b (N/m3) and surface tractions (f sources)
we know the geometry (V, Γ), the materials property (E, λ)
Hypothesis: small strain/small displacement -> some of the governing equations can be linear. Materials are linear-elastic (linear relationship between stress and strain).
- Equilibrium equations: linear, establish a relationship between stress and displacement, partial differential equations. 3
- Kinematic equations: establish a relationship between strain and displacements. Always partial differential equation. 6
- Constitutive equations: establish a relationship between stress and strain depending on the materials. 6
Equilibrium Equations
σi,j + bi = 0
Neglecting the dynamics effect (quasi-static conditions)
i: 1 When you have 3 equations, i is repeated, summation is implied.
σ11 / ∂x1 + σ12 / ∂x2 + σ13 / ∂x3 + b1 = 0
i: 2.
σ21 / ∂x1 + σ22 / ∂x2 + σ23 / ∂x3 + b2 = 0
i: 3.
σ31 / ∂x1 + σ32 / ∂x2 + σ33 / ∂x3 + b3 = 0
Boundary conditions:
σn = f (3.89)
σijnj = fj on Γ
▶ Slide: Basic Solid Mechanics
Linear governing equation → superposition principles ... small displacements, small strains and linear-elastic solids.
Constitutive equation: explicit relationship between stress and strain depending on the kind of materials.
Kinematic Equations and Constitutive Law
εij = ½(∂ui/∂xj + ∂uj/∂xi)
F - F
(ui = ui on the boundary)
Shear strain (E12,...)
Displacement gradient φi = δui/δxj ε = ½ (φ + φT)
Elastic body:
- natural state - stresses and strains = 0 (rest). Natural states are not so easy to be recognized, as some objects don't have a natural state. For example, body forces even when they're out of the body without blood on a table.
- External forces → increase of stresses and strains (in a non-linear way)
- External forces to zero → same path of loading
Linear mat. can be isotropic or not...
Linear elastic materials: σij = lijklεkl (like 4th order tensor)
When Ef = 1 equal mixture Cr = Nr
C0 D0 F0
lim the square cosθ Ef Df (transversal direction)
Heterogeneity → disturbance in inter/instrain fields we estimate the average strain within some kind of materials → we can determine macroscopic strain of the system ⟨Ef⟩ij, averaged on local domain of every material phase: Ei = i,j dV All particles are perfectly bonded to the surrounding matrix (no detaching on hyp).
Linearity → governing eqns → linear relationship between Ef and F through Ar
Ef = Ec + Cr ⟨E⟩ Ci: volumetric fraction Cot + Zf = 4
matrix contribution: Ec = Z + cfE ⟨E⟩ = E + Zf Cf Ar +
(the same for stresses)
Effective elastic tensor is a 1st order tensor
average stiffness tensor
Lf = ?
LD if no static mismatch between particles and matrix like: Lf → L0 → trivial selection, the second term has gone to zero.
1) Fictious problem: is the same of the real problem: ideal symmetry as assumption. Considering particles far apart from each other number interaction between them. With this approx
⟨Ef⟩ = E + E + f → Ef = TF ear = dF + If
Shelby method (low Cr: dilute systems) (dual approach with stresses)
ex: knowing geometries and Lo → [ →] D → A =
Shelby method with spherical particles: isotropic material.
2) Mori-Tanaka method: L0Lo0 → E0i same strain in the matrix
weakly coupling interaction between particles → L1f explains the same
⟨ EF ⟩ = E+ E2 [ Co + Zf Cf ] TF ⟨E⟩
At strain concentration tensor (dual approach for stresses)
even here with spherical particles we find an isotropic material. The method can be used for every value of Cr. Quite accurate (much more than Shelby method) used very cautiously.
3) Self-consistent method (the best one). Mechanical properties of the infinite fictitious matrix and the macroscopic elastic properties L = EF f = → but we want to calculate it. The equation depends on the solution itself → iterative method: first attempt L0 → etc --> Also the Shelby tensor is unknown.
L(E, i)
1 effective Poisson’s ratio
even L and 1 are implicit equation
interactions
Resume: 1) Ar = [TS] 2) Ar = IF[… []] 3) Ar = TF
When particles are not an ellipsoidal one we have complex anisotropic properties → complex models: use TEN to answer the strain concentration and tensor → then numerically you can find elastic tensor and so on.
Geometrical shape ratio n=not being ellipsoid →possibility to use analytical method.