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Exercise 10.1
We have to evaluate ∫∂ where Γ(x, y, z) = (z-y, x-z, y-x) and ∂ parametrisation of the triangle ABC
- A = (1, 0, 0)
- B = (0, 1, 1)
- C = (0, 0, 1)
Observe that ∂ is a closed curve and F is defined on R3.
We have to evaluate the circulation of F along the closed curve ∂. Let's see if we are lucky...
If F is curl-free, then F (being defined on R3) will also be of gradient type, and thus we can conclude that ∫∂ F = 0.
curl(F) = (∂yF3 - ∂zF2, ∂zF1 - ∂xF3, ∂xF2 - ∂yF1)
- 2y(y-x) - 2z(x-z), 2z(z-y) - 2x(y-x), 2x(x-z) - 2y(z-y)
- (1 - (-1) 1 - (-1), 1 - (-1)) = (2, 2, 2) ≠ 0
F is not curl-free ⇒ F is not of gradient type.
So, no shortcuts...
To compute the integral, we can compute it in two ways:
- either finding a parametrisation of ∂
- or using Stokes theorem ∫∂ F dγ = ∫T curl(F) ⋅ N dσ
Method ②
Given the assigned direction of ∂ (namely A ➔ B ➔ C ➔ A), the orientation of the surface T we should look out for T is the one pointing upward (third coordinate is positive).
Notice that T is flat, hence N can be found through the direction orthogonal to the plane.
We can find such a direction by taking the wedge product of two vectors in the plane.