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28/01/2022 N 0
= BI
Brot
bac 295k 25
:
= 6
pa 1 1
Ta
1 =
= .
. totale
87 (clinde.
22
Vi
MV 95
M ym
= 2
VI 0 0
= =
= .
. .
RPM
750 RPS
5
Mi 22
Mi =
= = .
%
as Timt
Pavi : TI
Ideale
zafzig =
.
Bi
Bi Bi
B - 28
= 1
+ +
o = .
Mus
G VI a
02825 g
= 0
: . zeV
pint Vi
G Via 1
- =
Mu
: .
RTI WV
(p2-pint
(Pint-P1)Vim Vim
Pa + 1534 2
=
= .
Y m
+ 2)
+1(2
Timt 3152
= :
5w
Qu Gcp(TinT +2) 687
=
= = .
(refemomideale pressione
l'int 30gK perdita
- di
,
MVIPINT
G bar
3052
spint 1
Vir :
= .
RTINT By 1)
+2(1 2
BE -
Timt 56k
324
3052 =
1 =
+
= . .
.
nv
4 WW
Q-Gcp(Timt-Timt') 470
= .
21/05/2022 N 0
= Brot 297k
288k 3 Timt
Ta
Pa 7
bat :
=
1 :
= .
= BToT/Bi
8235
B Bi
2 029
2
1
0
= T =
=
- =
. .
. VI i
RPS Se
48 667
2920RPM 4
=
M = =
= . 97
89yx
MV 0 0
=
= . . 46315kgisV (pint
PINT Bip1)
G Vir =
= 0
=
1 .
RTim +
PI
G Vi 84142
8
VIn =
yu -
= .
R + 2 22035ef
VI
VcI 2
=
= .
i kWV
(pz-pint) Vir
(Pint-P1)Vim +
Pa 83 5
=
= .
Yar
Le (pim
Vcy p2)
+ 1825
= =
- =
DaVci( 1)
K
LCI 865
244
= =
= .
K 2
graduale - 145
Ladd Li-has 37
grad :
: .
29/02/2021 1
N :
52x182 740RPM
G RPS
Kg/s 33
2 12
= m =
=
. .
62 52
92 08
06
Mm M 0
0 =
0 =
0
=
= .
. . 825 bac
B T1
3 288k
35 P1
mi 1 =
m 1
=
= = =
. .
B
Bi 2576
4
= = .
52
2 - : 2))
w
(2-S2)(z M(B
Xv 8266
=
: 0
- .
0692
P2vm
G V
x v 2
= =
- .
RT 2
v1 193142
V(1 r) 2
+ =
= .
2 se 35672
uV
V4 Bi 0
= = .
P2 p1(1-62) baz
92
0
=
= . (2) 245V
L PI(VI-V4)
m 152
=
= .
1
m - kW/
Pa : ma 3 904
: .
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