Esercizi Turbopompe

VALUOLA

& = 0,5Q; ny = 978; 2M 12 costant.

[h=10,348

NO SORRI MENTO

Hu = Ht + Y

itt = 02 +4

Po - PQg Hu

= 54,2m

[W = 12,76.589 1

2=32,308 KW]

Li= 2H = 623,345

12:= U (U + W Cos/32) > W = Li - U = 12,76461

192 = 2nd 2 = 353637 m/s

uz cosp

- 133 Kll/, com Q = 2 1 1 seu ß =0/197975 m /s

at

2

?

Hu' = Ht +Y' + hi

Q' = 0,5Q = 9,098987= w"/

2

X=0

y = Q y = 1m

Q

ngDE 12

Li'= 773,835 J

= 978

Li' = 2 Hu me Li = U (U + W r cota (3 ) Ye' cost poilie Mcost..

|Q = WETUDE CO . Wr = 41/4 polchré & cambie

wrz 9X/

Q

Hu= Li2y = 61,54699

g

hy = Ha - te - Y = (10,34 m

VnH

Hul Mest

Hut

Pa = P2 Hu = 32, 276 KW 82,28 KW

My Mv Ym

HE/

Q Q

= 0 13504 -> W/ = 4 U = 4, 1009/17

## TURBO POMPA 20/01/2017 # #

4 = 0,24= 1,79333; = 0,9; D = 0,142 m; l2/D = 0,1;

[ =9106 Pa = 11,65 kw] m = 2350

¡Q'=Q

1m = km (m cm) H =0,8 Hu

U = 02 - 21,19

GO

24 = 0,68 (2m 1 5 + invoudti) > [car = 4.30 m/s; m = 2731 pm

4= wr -> Wr = 4 ,238 Q = y RD W = 0,024739 2 /s

U2

4 = Li-> Li = 402,617 J/kp • 4 = 2011 + 9 + 1 ) 798 2 = 240 = -88 938557 +TO

4-20

91,06

32,0222mm -> Po = pag Hu = (11,649 KW)

?y ?o 7m

Hu= P =

Li= u + 4 1 _> tg (2 = _Wr U NO?

131

Li-u

L = u 2 + Qu 1 - 432=

STAD

REGOLAZIONE giu =)

Hu'03 Hu = 25,61776m

ny =0,78 2m = 09

2=0,97 2 = 0,25

Li = 2H4 = 363,46035/10;

My

Da cui

4' = 0,20877

-62,6757 +TU

Qu NO con queste fauve

4 -4

L1 = 20 (1 + 120 og (2 ) - dogan due le

422

La c a t c qu

vou Sto considerando romento

quié

y = Li' = 20 (1+p' wotpß ), Q = Q'u

Q Qu

ud

` =Wrz

Wrz

ma

4 = 4 4 Cr =W

Cr =Wr 4,238

0+ ouquet-Li = 0 -> U2 =20,30/3 = 0 m = 27 3024

60

-9070573

##TP_ 17-11-2021 H H

Hu=22μ Q = 3 l/s = 0,003 m/s, P=0,25, B = 115", m = 2950 xpm

2y = 0,8; nv = 0,98; 2m 996; { = 948;5=08 [Pa = 2,293 kW; C = 4,293 mm]

REGOLAZIONE > Q

+15= 2,5% (Yu Yu 5 imvouati)

AP = 25% y = 0,78

[ = 9003545 m /s; m = 3306 zpm ]

4 = 20 (1 + 9 cats P ) = 1,41348

Liu 19,5346 m/s = = 0,12647

Tum

m

L = 2Hu = 269,6925 JIKy

ny

Pe=PLQ Hu -2,293kW

2y2m 2v

REGOLAZIONE

Po = 2,86625 KW

5=4(1-4) = 0,2826

"l = Q/ns To D qu = 4,293 )

5' = 5 (1+0025 ) = 0,289665 = 5' = 1,31666

1-n!

Hu

Hu

Hy

Hv=Q

• Hu= (4-5) =

Hu'

• Q = √ { πD l q'u '

Q

Hu&Q

M

m

Q

Hu' =

Hu

214.60112

Pa' = 12. Hu'Q' = Pg Hu

252m7v

Q2

(0) Q' 2

Pa = 8,54494.10 0003545

-3

Hu' = 25,1μ

u = 20H14" - 21,89454 m/s

14'-3'

m = 60u2 = (3306 2pm)

TU D2

HHTP07-11-2023 H H

2 Scricts a pers libred 1z = 65m Y = 3m; 2y = 0,82; f = 135 %; n = 1420 pm

Cald = 0,06 ; d = 42 cm ; 2 = 0,95 { = 0,97 [W =

REGOLAZIONE

Q=045Q

21430,94

, m=m, ny = 0,78 (2√2m cost, No scorrimento)

Hu = Ht +Y= 68m

Hu813,2634 J/kg

I

Pela

Cibero

Az Li

ny

U2 = MTCD2 31, 2274 m/s

60

No scriments

Thv="

4 = Li/u21 = 1,66798 > 4 = 2(1+972)

4 = 4-2 = 0.16601

2 cot P

Pa=

[KW]

pm; Pou

C

W

Wr = 442 = 5,184061 m/s = W seu B -> W = 7,33137) ruls

Q = n { π dz & Wr = 0,15884193 m /5

P = upalu = 144,653 KW)

nyume

#4 REGOLAZIONE HE = He

Q=0.07147887. m /5

=

2

→ Y= (0,45) = 0,6075 m

Huhu + Ht.

?

2

Hu

423Ht

65

Q = War War = 0,45 war = 2,332827 m/s

Q

War

Li = ū (uz + War cota P ) = 902,302

Hu = Liny = 71,7646 m

g

hv = Hu-- Ht = (6,1571m)

Pe= Qp8 Hu = 72,223 KW

My YvYm

Lov

Q Q

Q

I can uz=ūz paidh m cost.

KW]

##TP_17/02/2023 # #i

LAMINAZ N-D

m = 3000 spir Bo 120 D2: 019 Q = 75 l/s = 0,075 m /s; y = 0.85

"PERDITE DISTRIBUITE IMP. PER METRO LINEARE DI TUBAZ J=0.1"

"PERDITE CONCENTRATE hue = 15m

L= 250m ; 22/02 = 0,1; } = n = 4m = 098 [Pe=36,04 kW; σ = 0.5977]

Tibariare

Se Q = 100; most: Pe = 45KW ;

hy = 0.93my, 2=2m-998

42 Drum = 29,845m/s

69

W2= 0/WET Diez soul = 7,951 41/3

Q = Wr2=wasen. 3

U

U2

= 0,2307

[hv = 2032 m ; σ = 0,817 ]

Cicco Cuso Ht = 0 com hwd = L. j = 25m

Hu = hwc + had = 15+23 = 40ur

Li= Hu2 = 461, 506. J/kg → Pe = PzQ Hu - (36,04 kw

My

= Li = 1,036 →

My 2m7v

2 (1-4)=93977

REGOLAZIONE LAMINAZIONE

2y= 0,954y = 0,8075 cony = hwpl - huc

U2

02

B

az

W

9.

Q = 67,5 l/s = 0,0675m /s

Hu 1

-(0.9)

(82) = 32,4

<y/

Hu

Y = (+lv)

mcost

Q Y

Pe = 820 Hu?

→ Fu = 52,719 m Hu>Hur Ho.

Ty?m?v

hv=Flu - Y = 20,32 m

u = U

Hu = 640,2665 J/kg

Li

ny

Q

W =

14=0

Q

Q.

= 1,4376; = 4

=(0,3167

2 (1+Qtz P )

↑

7,1559 m/s = W seuße = 0,20765

U2