Heat exchanges
Heat exchanges 1es 0,24ns inedite-15mm -45mmDi Da; in 100°C -30°C Thi te= i, ( ) ?602i. tuo => 3,2515¥tfgie131propense -µ-0,138ftKpiops.ua#cp=417efgrM=725-fo-6k=Q625YnPr--4,85 infetto( ) )ThpTn Tai'mia i -Cpu -,-8524W a?t' 2T LUadtemg--9- 40,2°CttcTc = =io, , rizcpcÉTÉ ( )14049,54Red water turbolente→> fi pertsntm0,02312%Nn 0,4con me- .I In89,98 ↳ 2249,5 the of instead oil TÈDaDu Di f0,02 mi= Un- -= -m= IIII umaniRe tdùg. .. ;Dtgldoµ D-4 min- 55,97 Radio == laminariµNu È5,63 ho= =. ' nEho 38,85= m'k Sound the internal I external connection selfnow an .!%unastà! 43,22 ÈÈ 38,19UUastem ==q = 9 65,78« je m=Heat exchange2es ».
Flow heat exchangecross
-100%7 ( )hstgasUn-100°C300°C TuoTh o=;, (-125°C )35°C water l' Te coedEs Ii iniè = ., È? Eterne -4197Ate cp1 100¥ho vii.=3 -Una T mikIo using ntueah.vnobtain AhI can ( min% butta4197 CheCernie neodCp =-, balance vsimg energy Cntth ) )CeltoTha Tai=i - -,cosÌ 1888,65che e-CheCc Cn> Cminso -I Cmindtne 0,755E == =Ft9mm cnn.in/Cmw=ylaphs 0,45 -2NTUusiny nt 37,77Ah mie-> exchange3 Heates ».
HX design previous exercise
40mi 250°C-1,5Ah100 ThiUn -1000in = cp=µ 35°Csina.1ksjtc.ie 4197cp =Tae? ?? Tuoa = =1500¥Che Cmim=nihcph =4197¥Cc - RNTU-lhg.ae?-- III.2,67 936ECmimlthi-tc.it ?6hosWq--nincpwlThi-Tn.oEqmaeE- 0,82 q = =) 73,33°Cthis - 98,1°C Te =.,
Exchange Heat4es
25mmN' D'30000 eachtwopassescondensa3.to#kIsfEi=1kgis)Te,i--110001% -18Who 9=2 in. ( )phusechanginy50°C20°C Tu Const==?? LII. = =o Ègn "" 4179 855.107ms9=997 µwater pre ↳ = .PrK 9613 -5,83- --qeniccp.co/Tc,o-Tcii)ntu.li?n=UtdlCmin1hb/sO35,95CTuo = NTU.cm/.n-L ← UTDfiIm -59566,76Rei turbolenti- Pri "" 307,61Nu Re0,023 -=; 7542,6¥hi = km'4474,49Wh✓ = know that cnn.chand we =p1,254.108( minacce sino cp >- ,) 'Cminltni Tci 3,762.10 E- 0,532=9mm -- E) %lnltNTU 0,76 4,52mi= = -- -- ,
Heat5 exchangees
rs. 40°C Oil90°C ThisTh coolingi. >, 20%4=0,33502 "10°C Tao water %Te in--, È-100k¥ -41868? cae'U f- =1) double hxcfrpipe tuoshell2) water passalpassone ,3) tuo tubeshell and fourpasse passa, 55,268.18Vaste1) incpdt9 g-= -_dT 34,76°C stianodtem =) 30staentità7,95miA- }thermalcapacitypi-ffa.ae2) ratio of 0,6F-Petiteperformance qgzg vsimgrigdfpth=TaiTui - ,'A 13,25M=3 == #.en3) right graphs 93=Dthe F-using ,reqùvdheatt8,55mi thea. is area." ? condensaSteamsingle? te pass%E6.fhkksdrysaturatedste.am" 60225000 Theii. TopTe D.30°C-20°C 25mm 22,5mmDi- = =i, I100 1,5nsInktube Un == EtRisp-4500%4 » =Nnho 0,024=- "kffgkk-9609pt-fqo.iokbrfm -4,1819=997water Cp} -papa 6,13Prehggltw.GE/=2358,5kEgCmcu=Ch"? ? tuboinO 0,59 inUnit .ge= - un- 665N'sina.pe 392,25k¥2466,79Cc Cmim >e-= IÒWhgg.inpotenza richiestala 1,64sarà q=--tuttofar fluidocondensare ilper atubi" 'la ottenere i9 perqcena o FITREQOTIM' Pdtem 30 sta 40stiq >ÈI 34,762AtmRe 37513,67 -- -_ 5107,75%4 -zlm% mi"RINn -188,71 .io1,19hi ,= = WÈ.it#Fi--2452isYnqt- 6053,66¥V. m"ÈHotel 4,07M↳709,1 m' =shellandtubehx2estm-55.cn:74. Kris 90°CI. Teinsiste 20°Cwater -i. -,-145°Cshell 90°Chotengimesil.tn Thesimile ;- )
Scarica il documento per vederlo tutto.
Scarica il documento per vederlo tutto.
Scarica il documento per vederlo tutto.
Scarica il documento per vederlo tutto.
Scarica il documento per vederlo tutto.
Scarica il documento per vederlo tutto.
-
Esercizi prima parte Advanced Heat and Mass Transfer
-
Formulario Seconda parte Advanced Heat and Mass Transfer
-
Domande Teoriche prima parte Advanced Heat and Mass Transfer
-
Formulario prima parte Advanced Heat and Mass Transfer