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*I
at least as well as s against every strategy of the other players, and against
*I
some it does strictly.
CHAPTER 4
In this chapter we’re going to study a second solution concept form strategic
form games: iterated elimination of dominated strategies (IEDS).
DEFINITION: a strategy s is dominated by another strategy s if the latter
*i ’I
does at least as well as s against every strategy of the other players, and
*I
against some it does strictly better.
If a strategy is not dominated by any other, it’s called an undominated
strategy.
7 PLAYER 1 \ PLAYER 2 NORTH SOUTH
HIGH p1 (H , N), p2 (H , N) p1 (H , S), p2 (H , S)
LOW p1 (L , N), p2 (L , N) p1 (L , S), p2 (L , S)
Consider the same example from chapter 3: in this strategic form “low” is
dominated by “high” if and only if (H , N) (L , N) and (H , S)
π ≥ π π
1 1 1
(L , S) with at least one of those inequalities being strict.
≥ π 1
Generally consider a game in which player i has many strategies: if there is a
dominant strategy, all the remaining strategies are dominated; if there is not a
dominant strategy there may not be any best strategy. Now using the IEDS let’s
find the solution of the following problem:
PLAYER 1 \ PLAYER 2 LEFT RIGHT
UP 1 , 1 0 , 1
MIDDLE 0 , 2 1 , 0
DOWN 0 , -1 0 , 0
Let’s start with player 1: we can easily see that “down” is dominated by “up”
and “middle” because she gets always a lower payoff, no matter what the
other player will choose. It’s important to remember that for a player is useless
to play a dominated strategy because there will be always a strategy that gets
a higher payoff, so we can “eliminate” “down”. Now it’s player 2 turn and he
has to choose between “left” and “right” related to the two other strategies
remained. “Left” will always offer a higher payoff than “right” for player 2 so, in
order to reach the final result, we have to consider a third stage in which player
1 have to choose between “up” and “middle”. For him, the best strategy is
always “up” rather than “middle”. The chosen strategy (UP , LEFT) is said to be
reached by iterated elimination of dominated strategies (IEDS), the
game itself is said to be dominance solvable.
The advantage of this concept is inherent in the simplicity of the dominance
concept: in fact if a player is convinced that a strategy always does worse than
some alternative strategy, then he will never use it. The disadvantages of this
concept are the layers of rationality. Let’s assume that the strategy (UP , LEFT)
costs a fee for player 1: he will not want to choose it anymore, so the game is
not anymore rational.
CHAPTER 5
In this chapter we will look to the most famous solution concept for strategic
form games: Nash equilibrium.
Suppose that you have a strategy B that is dominated by another strategy, say
A. We have seen that the player will always choose strategy A due to the
different and higher payoff than strategy B. Now suppose that the player has
some ideas about the other player’s intentions. In that case he would choose A
8
provided it does better than strategy B, given what the other player is going to
do. Hence, you do not know that strategy A is always better than strategy B
against all the enemy’s strategies, what is important to know is that strategy A
performs better than strategy B against a specific strategy. Indeed strategy A is
called best response against the known opponent’s strategy. Typically you will
not have the certain strategy of the enemy, you will have a guess about his
possible strategy choice. Of course, the guess might be wrong. If it is correct
and also the other player plays a best response, you will be in a Nash
equilibrium.
Two questions about Nash equilibrium arise:
1- Do we know that every game has a Nash equilibrium? Recalling the
dominant strategy solution or the IEDS, we can easily see that these
concepts yield no solution in many games.
2- Do we know that a given game will have exactly one Nash equilibrium?
We know that in many games there is more than one Nash equilibrium,
but the question is which one of them is the most reasonable?
Let us now show several examples:
EXAMPLE 1: BATTLE OF THE SEXES
HUSBAND \ WIFE FOOTBALL OPERA
FOOTBALL 3 , 1 0 , 0
OPERA 0 , 0 1 , 3
We can easily see that using the concept of best response, in green we might
see the best responses of player 1 against the two opponent’s strategies and in
red we might find the best responses of player 2 against the two opponent’s
strategies. In this game (FOOTBALL , FOOTBALL) and (OPERA , OPERA) are both
a Nash equilibrium.
EXAMPLE 2: PRISONERS’ DILEMMA
CALVIN \ KLEIN CONFESS NOT CONFESS
CONFESS 0 , 0 7 , -2
NOT CONFESS -2 , 7 5 , 5
Without using the concept of best response, we may use the previously stuff
about this game: we know that confess is a dominant strategy, but this is the
same thing as saying that both players are choosing the best response. Hence,
the only solution of this game is (CONFESS , CONFESS).
9
The general relation between Nash equilibrium and IEDS can be summarized by
the following result: every IEDS solution must be a Nash equilibrium but vice
versa, every Nash equilibrium isn’t an IEDS solution. For instance:
FELIX \ OSCAR 3 HOURS 6 HOURS 9 HOURS
3 HOURS -13 , -8 -1 , -4 7 , -4
6 HOURS -4 , -1 4 , -1 4 , -4
9 HOURS 1 , 2 1 , -1 1 , -4
Using the concept of best response we should find three Nash equilibrium: (9H ,
3H); (6H , 6H) and (3H , 9H). Using the IEDS concept, “6 HOURS” and “3
HOURS” are dominated by “9 HOURS” for player one and is the same for player
2. Hence, the IEDS solution is only one: (9H , 3H) that is also a Nash
equilibrium.
CHAPTER 6
In this chapter, an application of the Nash equilibrium concept to a model of a
duopolistic market, the Cournot model, will be discussed.
Historically speaking, economists has spent the greater amount of time and
energy available studying two extreme forms of markets: monopoly, where
there is a single firm, and a perfectly competitive market, where there are
many firms in perfect competition. The reason for which we’ve made this
distinction is that typically a monopoly has no reason to take into consideration
the other competitor’s choices, because there are no competitors in this kind of
market. However, in reality, the most prevalent scenario is one in which there
are many firms in each given market. In this case, a company might guess the
action of the competitors in order to anticipate them and choose the best
response against them. So what should do the company? If they rise up the
prices, the market will match perfectly this delta or they are going to lose
customers? The Cournot model gives some answers to this problems.
In the model proposed by Cournot, two firms compete in a market for a
homogeneous product. In other words, consumers are unable to distinguish
from which firm the product that they have bought comes. Therefore, the two
firms have only one demand curve in the market that is given:
Q=α−βP
>
Say that , and Q = Q1 + Q2 that represent the sum of the
α 0 β> 0 α Q
−
P=
quantity produced by the two firms; the price will be: . If we use
β β
α 1
A= B=
and , the new price equation is: .
P= A−BQ
β β
10
Now we’re going to explain the Cournot model with real numbers: A = 10 and B
= 1, the inverse demand will now be P = 10 -Q.
Let’s assume now that the cost function does not vary with the numbers of
units produced and it’s the same for each firm. Formally, the cost of producing
quantity is Qi equal to cQi, in which c > 0 and i = 1,2. Now the question is: how
much would each firm produce? To answer at the question the firm has to take
two steps:
- Make a guess about the other firm’s production. This step will reveal at
the firm an idea about the likely market price: for instance, if he thinks
that the other firm is going to produce a lot, the price will be very low no
matter how much it produces.
- Determine the quantity to produce. In order to determine the quantity to
produce the firm has to weigh the benefits from increasing production.
A Nash equilibrium will be obtained if both issues are satisfied.
Let’s now consider firm 1: if it was the only firm of the market, it decisions are
able to determine the market price. It could compute the profits from selling
different quantity levels and pick the quantity that maximizes profits. As a
start, what firm 1 might do is ask, if firm 2 is going to produce Q , what
2
quantity should it produces in order to maximize profits.
What we should know form the above assumptions is that the price market, in
this case, is equal to: A – B(Q – Q ), say that the total production is Q = Q +
1 2 1
Q .
2
The revenues of firm 1 are therefore [A – B(Q + Q )]Q . Since costs are cQ , the
1 2 1 1
total profits are given by [A – B(Q + Q )]Q – cQ . Hence, the quantity that
1 2 1 1
maximizes the profits in this precise case is: Max [A – B(Q + Q ) – c]Q .
Q1 1 2 1
There is a maximum profit quantity, say Q , which we can compute with first-
*1
order condition to the problem. As a result, we have that Q is a best response
*1
A−c−B Q 2
of firm 1 to a quantity given produced by firm 2: Q = . Now let’s
*1 2 B
describe the reaction function R (Q ) that will denote the best response of both
1 2
firms.
11 A−c−B Q A−c
1 Q ≤
, if 1 B
2 B A−c
>
Q
0, if 1 B
Using the same logic, we can observe also the reaction function R (Q ) for firm
2 1
2.
In the above graph, we can find both best responses of the firms. Hence, this is
a pair of quantities for which:
- R (Q ) = Q
*1 *2
2
- R (Q ) = Q
*2 *1
1
In other words, this pair is a Cournot Nash equilibrium of this game.
From the above graph is easy computable the quantity, the price and the profit
for each firm: A−c
- Per-firm quantity: 3 B
1 2
+
A c
- Price: 3 3 2
( A−c)
- Per-firm quantity: 9 B
Let’s now assume that the two firms are operating as a cartel. This is possible
only if they coordinate their production decisions. As a cartel, their aim is to
maximize the total profits. In this case, the production function is: Max = [A
Q1,Q2
– B(Q + Q ) – c][Q + Q ]. The difference between these two cases is that in
1 2 1 2
the cartel case, the firms acknowledge explicitly that their prof