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Review of Fluid Properties
Pure Fluids
Ideal Gases
pV = nRT
pV = RT
The kinetic energy is stronger than the Van Der Waals forces
Subcooled Liquid
Saturated Liquid
Critical Point
Vapor
2 phases
Saturated Liq. + Vap.
Saturated Vapor
Andrew Curve (saturation curve)
Supercritical Fluids
Subcritical Fluids
Vapor Phase
How to model the behavior of pure fluids, so how to calculate the dynamic properties? It depends where you are in the diagram:
- T > 3 Tcr, p < pcr ideal gas model
- T < 3 Tcr, p > pcr real gas (vapor)
p v = R T (Equation of State)
Z = v(p,T) / (RT / p) (compressibility factor)
The real gas effect increases if T is lower and p is higher.
Estimation of Equation of State for Real Gases:
- Tables and Diagrams with experimental data
- Best-Fit Function of experimental data
- General Equation of State, trying to model also the real gases
Ex: (p + n2a / v2)(V - nb) = n Ru T (Van Der Waals)
- a = measure of the average attraction force between molecules
- b = volume occupied by the molecules
∫V ∂ρ/∂t dV + ∫Sin ρ Vr v dA + ∫Sout ρ Vr v dA + ∫SL ρ Vη dA + ∫SR ρ Vη dA + ∫SP ρ Vr v dA = 0
ṁin ṁout
∫V ∂ρ/∂t dV − ṁin + ṁout + ∫Sη ρ Vr v dA + ∫SP ρ Vr v dA = 0
Steady Flow Condition:
for every property of the fluid (p, h,...):∂ϕ/∂t = 0 (for ∀ point of V)∑IN ṁi = ∑OUT ṁi
Steady Average Flow Condition:
∂ϕ̅/∂t = 0 where ϕ̅ = 1/T ∫tt+T ϕ(t) dt∑IN ṁ̅i = ∑OUT ṁ̅i
Examples without chemical reactions:
Valve
- Mass Balance: ̅m1 = ̅m2
- Atomic Balance: Ai, T = Ai,2, T
- Ni, K = Ni, K (no chemical reactions)
- Energy Balance: Q̇IN - ẆOUT + ̅m1hTOT,1 = ̅m2hTOT,2 = 0 (y adiabatic)
hTOT,1 = hTOT,2
h1 + V12/2 g z1 + eCH,1 = h2 + V22/2 g z2 + eCH,2
h1 = h2
Turbine / Compressor
- Mass Balance: ̅m1 = ̅m2
- Atomic Balance: Ai, T = Ai,2, T
- Ni, K = Ni, K (no chemical reactions)
- Energy Balance: ẆOUT = ̅m1(h1 + V12/2) - ̅m2(h2+ V22/2)
BLADE POWER (power extracted from the fluid)
MECHANICAL POWER: Ẇmec = ẆOUT ηmec
ELECTRICAL POWER: Ẇel = Ẇmec ηel
Mixtures
In general the stream of reactants R can be a mixture of species, how can we determine the enthalpy and the chemical energy of a mixture?
- hTOTR = hR(T,p) + VR2 / 2 + gzR + eCNR
- Chemical Energy
eCNR = mΣk=1 YR,k eCNK
- Enthalpy
hR(T,p)
- if R is a pure fluid: h(T,p) is computed using the relations of that fluid
- if R is a mixture:
- real mixture: molecules of different types tend to interact, with forces
- ideal mixture: there are no forces between different molecules
- ideal mixture of ideal gases:
hR = nΣk=1 ynk hk(T,p,xnι) ↳ concentration of the other molecules
hR = nΣk=1 ynk hk(T,p0k) ↳ partial pressure
hR = nΣk=1 ynk hk(T)
Example:
hTOTR = mΣk=1 ynk Cp,k (T - Tref) + VR2 / 2 + gzR + eCNR
Cp,R = Cp of the mixture
Parallel Flow
the slope of the lines depends on the mass flow rate of the fluid:
Q̇ = ṁHOT CP HOT (T1 - T)
T = T1 - Q̇ / ṁHOT CP HOT
dT / dQ̇ = - 1 / ṁHOT CP HOT
Counter Flow
To increase the heat transferred, instead of increasing the length of the fins, is better to increase the density of the fins.
In order to optimize the heat transfer we have to find the right combination of length and density.
Design Procedure of Direct Transfer Heat Exchanger
Problem to be solved:
- Input data: design specifications:
Determine the best HX type and its design (area, n° of tubes, diameter, thickness and length of the tubes and of the shell)
Steps:
- Determine the heat to be transferred Q̇ = ṁₕₒₜ Cₚₕₒₜ (Tₕₒₜ ₍ᵢₙ₎ - Tₕₒₜ ₍ₒᵤₜ₎)
- Select the construction type
- Set the desired speed for the two fluids → h
- Evaluate the heat transfer area A using the heat transfer rate equation
- Work out the geometrical parameters of the HX. These variables cannot be selected independently, but the combination must satisfy the following equations:
- Aᵢ = π Dᵢₜ Lᵢ Nₚₐₛₛₑₛ
- Sᵥ = π Dᵢₜ² ṁ̇ / ρ V Nₜ
- Preliminary mechanical design or check
- Rating calculation/simulation CFD: We fix the flow rate and the temperatures at the inlet and we fix the geometry, and we calculate the outlet temperatures. With the software we look for the most accurate estimate of Q̇ and the outlet temperatures, because we need to meet the specifications
This situation can lower the efficiency of the engine.
How do we solve this problem, so how can we decrease w?
- reducing the area of the HXw = w (̇ (̇)wmin (whot - wcold))
- reducing the flow rate of air reducing the rotational speed of the fan, or the flow rate of water with a bypass valvew = w (̇ (̇)wmin (whot - wcold))
- recycle across HXw = w (̇ (̇)wmin (whot - wcold))
In the previous example let's assume to decrease the flow rate of water:
̇wH2O = 0.6 ̇H2O
w = w (̇ (̇)wmin (whot - wcold))
(̇)whot: 0.6
(̇)cold: 0.5
(̇)wmin = (̇)wmin
NTUw = Uw Aw / (̇)wmin = NTUs? → NTUw = NTUs
̇w has decreased, so w will decrease, but U mainly depends on hair, so Uw = Us
Crw = 0.83 ≠ Cs → w ≠ s