E E
µ µ E µ
µ µ
γ γ
e →
= <
=
ρ ρ E ρ E ρ ρ
γ γ
en,Comp Comp Comp Comp en,Comp
Pair:
−
E 2m
µ µ E µ µ
γ e
e ≃
= =
ρ ρ E ρ E ρ
γ γ
en,pp pp pp pp
4.2 Photoelectric effect
The photon interacts with an e- of the atomic shell, it’s an interaction in
the first orbital of the atom, near to the nucleus. When the photon arrives
Figure 16. Photoelectric effect
it’s completely absorbed by the electron, which escapes; then an electron
of the outer shell can fill the empty place. In generally, when you have
photoelectric effect you have also other radiation emitted by the atom, due
17
Figure 17. Spectrum of Photoelectric effect
to the fact we have electron that move between orbital. We could have also
another effect: this photon can escape the atom or can be taken from en
electron that escape the atom, this is the Auger effect. The spectrum is
the sum of:
⇒
e- of the outer (M, L, K) shell fills the free shell Emission of X ray;
Sometimes energy released not emitted as X ray but absorbed by e-
⇒ Emission of Auger e-;
This is an inelastic interaction: γ kinetic energy used also to free the e- so
we have an Energy threshold. −
E = hν E
e b
Where hν is the energy of the photon, E is the kinetic energy of the electron
e
and E is the e-binding energy.
b
4.3 Compton scattering
Photon interacts with an electron of the atomic shell, it’s an interaction
which belongs to the outer shells of the atom, because e- is considered “free”
so this is an Elastic interaction and we don’t have no Energy threshold.
Photon survives after the interaction and Almost all energy is transferred
to e-. The energy of the emitted electron has a particular distribution: for
an incident photon of about 0.5 MeV you produce electron with a peak of
a bit less than 0.5 MeV; tipically the e- produced are closed to the nergy of
the photon. 18
Figure 18. Compton scattering
Figure 19. Spectrum of Compton scattering
4.4 Pair production
The photon arrives close the the nucleus, feels a strong field and disappears
produce a couple e+e-. To have this process you need the nucleus: it’s
impossibile having a gamma that disappers in vacuum alone and producing
a pair, due to energy momentum conservation. In this case we have an
Figure 20. Pair production
· ·
energy threshold equal to 2 m = 2 511 KeV = 1.022 M eV . Of course, as
e
we said there must be Square Quadri-momentum conservation: photon=0,
19
e + e− > 0 so we need something else in initial state (nucleus recoil).
4.5 Cross section Figure 21. Cross section
The cross section is the probability of interaction between the beam and
the target. The dimension of the cross section is an area, so we can imagine
that it’s the area superimposed between the beam and the target. The unit
−24 2
is the barn = 10 cm .
The cross section strongly depends on the material (on the Z) and it deacrease
with the energy. Let’s see the cross section for these 3 effects:
4 3.5
∝ →
Photoelectric: σ Z /E Important in heavy metal and in low
5
∝
energy range; (σ Z /A)
∝ → ∝
Compton: σ Z/E linear attenuation wrt energy;(σ Z/A)
2 2
∝ → ∝
pair: σ Z /lnE almost constant at high energy (σ Z /A)
In the energy range of 1 MeV, for example, we have most only photoelectric
effect, and at 10 MeV we have 50% of pair and 50% of Compton. If we
have Compton effect, the photon survives so after this maybe we can have
photoeletric effect.
The human body is similar to the water, so it’s useful to remember some
number: for 1 MeV the cross section is near 1 barn; tipically a good value
of σ for a photon in water for energy conventional for hadrotherapy isn’f far
from 1 barn. 20
Figure 22. Cross section vs energy
5 Charged Particle: interaction with matter
The interaction can happen with the atomic eletrons, with the nucleus,
passing near the nucleus or interaction with eletrons and nucleus. All these
Figure 23. Charged particle type of interaction
processes are EM process so we know all the characthistcs of them. These
are the main interactions in the hadrontherapy. We can have also nuclear in-
teraction and this is a problema because at that energy not all the properties
of nuclear interaction are known.
5.1 EM interaction on atomic electrons
This is Inelastic Collision: the proton arrives, it gives some energy to the
e, one part of the energy is used to break the bond (ionization of atom)
and the other one is given to the eletron in kinetic energy. Infact the is no
21
conservation of kinetic energy (part of the energy loss by proton is to free the
6
≃
electron). This is a frequent process because σ 10 barn: we have a big
particle (p) that gives its energy to a small particle (e), it gives only a small
part of its energy, energy loss but negligible deviation (mass projectile >>
electron mass) (γ give all its energy in just one shot). We have Hundreds of
collisions, it makes no sense to speak of cross section, but of energy loss of
the all processes. We can have 2 types of collisions:
⇒
Soft collision: Atom excitation disexcitation emitting photons;
⇒
Hard collision: Atom ionization electron emission (δ ray)
As we can see in the figure we have an ion that ionizes a lot of time the
material and each time produces some δ rays.
Let’s see why the cross section is so big. We said that Cross section (inter-
action probability) is almost equal to geometrical surface, so we can write:
2
∼
σ π(R + R )
1 2
−24 −2
Remember that 1barn = 10 cm . What is the ratio of probability
between this process and the other one?
σ S
atom atom 8−10
= = 10
σ S
nucleus nucleus
The interaction with the electron (atom) is much more probable than with
the nucleus, because of course the dimension of the atom is much bigger.
−8 −16
2 2
σ = π(10 ) = 10 cm = 100 M barn
atom −12 −24
2 2
σ = π(10 ) = 10 cm = 1 barn
nucelus −13 −26
2 2
· −
σ = π(2 10 ) = 10 cm = 10 100 mbarn
pp 22
Bethe-Bloch formula Due to the fact that this process has a probability
in practical equal to 1, it’s Make no sense to speak of cross section, instead
we speak about energy deposited dE/dx. It’s important to evaluate the
energy loss in each dx, because it’s important to deposit a lot of energy in a
very little region in order to create a not reparable damage in the dna. The
Bethe-Block Formula or stopping power describes the energy deposited by
the passege of a charged particle in a medium and can be written as:
2
2 2 2 2
2
dE 4πN m c e 2m c β δ
ρZ z C
e e
A 2
− − −
ln β
= .
2 2 2
−
dx A M 4πϵ m c β I(1 β ) 2 Z
0 e
U
When δ is density correction, important at high energy and C is shell cor-
rection, important for low energy. We can divide this formula into 3 parts:
some medium properties (red), some general constant (green) and the beam
characteristics (z, β) (blue). This formula depends on the density, because
of course the beam encouters more material if the density is high,; it depends
on the ratio of number of charged proton over A, this is not very important
because this ratio is more or less 0.5. So the importat thing of the medium is
the density. This formula depends also on the beam properties: it depends
on the z of the beam, it’s not true that is the z is larger it’ better because
larger z of the beam implies also side effects from nuclear interaction. This
Figure 24. Behaviour of Bethe-Bloch
formula has a behaviour like this in this plot: at very low energy dE/dx is
very high, because the kinetic energy is low so also β is low; then we have
the minimum and then a relativistic rise but and a Fermi plateau. Notice
that if the energy of the particle is zero i expect that dE/dx is zero, because
i can’t create something from zero, but de/dx is infinite. This description
can’t be good for low energy and we need Cell coorection in which at very
low energy the hypothesis that the atomic e- is at rest falls (in bethe-bloch
formula we have the hypothesis that the e are at rest, because their velocity
23
is very low with respect to the velocity of the beam). The most part of the
energy of the proton is released when it has low energy, at the end of its
range. We can have also some other correction like Barkas effect: if the
Figure 25. Low energy range
particle that enters in the matter is a positive particle it’s attracted by the
electron of the atom and proton can takes one of these and in this case its
effective charge decreases; on the other hand, if a negative particle enters in
the material, it rejects all the e of the atom clouds, so the interaction can
2
be different. There are also Minor correction which depends on the Z , that
are important at low energy. 2 2
Let’s see how it’s important the ratio z /β : let’s take 3 different particles,
all with z=1 at E = 30 MeV, but different masses.
kin
dE 1
→ ⇒ − ∼ −
proton (m=939 MeV) β = 0.25 [14.4 0.06] =
dx 0.06
240 a.u
dE 1
→ ⇒ − ∼ −
pion (m=140 MeV)= β = 0.57 [14.4 0.32] = 44 a.u
dx 0.32
dE 1
→ ⇒ − ∼ −
muon (m=105 MeV) β = 0.63 [14.4 0.39] = 36 a.u
dx 0.39
All the part in the bracket is very similar. Having the same β doens’t mean
having the same energy, but the same enrgy per nucleon (proton with 10
24
MeV, the same beta is in Helium with 40 MeV).
Bethe-bloch depends n the crossed matter in these parameters: ρ (density,
can vary orders of magnitude), Z/A: range from 0.5 to 0.42 and I, that is
mean excitation energy (ionization potential): range from 19 eV for H, to 820
eV for Pb. In a low density material we have Few collisions, some with high
→
energy transfer so the Energy loss showa large fluctuation Landau tail;
in a high density material we have many collisions so the Energy loss show
→
low fluctuation Gaussian shape (e-producedby ionizationare called δ
(ray)).
We need to unterstand how much interaction has the proton crossing the
matter: if we take a proton of 200 MeV, the e
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