Disequazioni: [math]{\left\lbrace\begin{matrix}\frac{{{3}{x}^{4}{\left({x}+{1}\right)}^{3}}}{{\left({x}^{2}+{1}\right)}^{2}}\lt{0}\\\frac{{{\left({x}^{2}-{3}{x}\right)}^{5}}}{{{2}{x}{\left({x}-{1}\right)}^{2}}}\ge{0}\end{matrix}\right.}[/math]