Integrale generale
y'' - 9y = 1/1 + e3x
y(0) = 1
y'(0) = 1
P(λ) = λ2 - 9 = 0
λ1,2 = ±3
Δ > 0
Y(x) = c1e-3x + c2e3x
W = e-3xe3x-3e-3x3e3x
c1e-3x + c2e3x = 0
3 + 3 = 6
y1 = 1/1 + e3x
y1' = 0e3x-3e-3x -e3x/6(1 + e3x)
y2 = e-3x0-3e-3x1/1 + e3x e3x/6(1 + e3x)
γ1 = ∫ e3x/6(1 + e3x) dx = 1/18 log(1 + e3x)
γ2 = ∫ e-3x/6(1 + e3x) dx = 1/18 ∫1/t2(t + 1) dt =A/ t + B / t2 + e / t + 1 = 1/6(t + 1)At2 + A
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Esercizi analisi matematica II
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Analisi matematica II - esercizi
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Esercizi Analisi matematica II
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Analisi matematica II - Esercizi