Temi d’esame Scienza delle costruzioni

Formule e calcoli strutturali

01/02/19 GrdL=12 GrdV= A+2+2+2+2+2+1+3=13 ABEFGDF ∑ moltipier χ_th = ql² / cEJ Δ = ql⁴ / cEJ ISO GrdL=9 GrdV=9 FX=0 FY=0 MA=0 N=0 T=-qb MN - qb l² - 2Ve=0 -qb l² M=qX² / 2 (qX³ / 2) MAdFSH = qb l² MH = ql² FX+H_c = 0 qe² qb² / 2

Calcoli di equilibrio e reazioni

GrDl=12 Gdv= A + 2 + 2 + 2 + E + 1 + 3 =13 sono invariuper AO B F H G D F E χ^th = ^qb2/_cL Δ = ^qL2/_cL ISO GrDl=9 Gdv = 9 FX=0 FY=0 HE= HO² - qb=0 / VA -VE=0 - ⌋/VEMA=0 / - qb₂-ho-ho₂ + HO2-VE₂ b = 0 + Mg = 0 + MO² = 0 e + mg = 0 ▶ HE⁰ - qb - /HD + Mg=0 -MO +2HE = 2VE VE = o - /HO² = Ho HE²=0

Sistemi di equazioni

X₁ - qb² X₃ -qL² + HN_c = 0 S.1 FHMH 0Fx=0Fy=0MB=0 HD - qb - ϕ - qb + R = 0 → HD - 2qb + R-VC + vb - qb = 0 → VC = vb-2qb + VC qb + HD=0-2qb + VC + HD - R = 0 → VC = R/2 VC = R/2 VB = R/2

M - qbx1²/2 + qbX1 = 0 x1 = ± N = 0 T = 0 M = -qb_x2 ²/2 = 0 V/2 N = 0-T = -qb - qb_b(b+x3) - ϕx3 = 0 M = -qb_x3 ²/2

Ulteriori calcoli e formule

• M - qb²/2 + qbX1²/2 + qbX1 -RX1-2qbX1 + RX1 + 0 - Rb + qb2/(qbX1HS = -qb²/2 + qbX1²/2 + qbX +-qb²/2 + RX2 L = R/2
• Δ-1 qb LINT = ∫ -M dx = ∫ = -qb_x2²/2 + qbX1 - RX1 dx1 = ∫ ¹₀-qb²x₃/2 - qb_X3 ⁴ +-qb³/8 = qbx₁³/3 - qbX1²/2
• xb₃ - qb₃x₃ - qb³x₃ ³ - M /24 x²-qbx3/8 - qb ³ = 0 +- γ = R XB + RX₂ - qb - qb²/8
• - γ = R/2 + RX₂ - qb² = -qb²x₃ ³ / Rrpqb - qbx1²/2 - qb³/12 -γ Ex / 8 - R= -qb²x₃ ² - qb²/8 12RX₃- γ -qb²/82X 24/5
• -q - Rx/24 QB(3 - 4) + (1190 -- bqb/6 -^2R₃ -3.23Rxb³ (3 - rq b) = 0(3/24/ - 11.5 -2-37 - 4R/12(12/5 + 3E)R = 20/24 = 17

PERSeq venzN = -ql² T = -qb T(H)(b) = qb M = qx²/2 9x3N = -ql² T = -qb M = -ql²/2 M(H) = -qb T = -qb/2 BECOS(SIN B) H(C) = -RV(C) = -R/2 V(C) = -R/2 - qb/2

Calcolo delle reazioni

Fx=0 Fy=0 Hc=0 R+2q/22 vb=q/2 H(0)=-ql²/2 T =-qb/2 N = 0 T = -R -qb -qx1 = 0 M = qb²/2 -qx4 -Rx4 + qx1x₁/2 M = -qb²/2 -qx4 -Rx4 - qx₂/2 N = RT = -qb +R +qb = 0 -> T = -qb, R/2 = 0- (R - qb)x₃ = 0 M = -qb²/2 + qb x₃/2 - R x₃/2 = 0 M = -qb²/2 qx₃/2 - b x₃

M(0) = -qb² M(b) = Rx₃/2 M1/21/2 M₀ X₁ X₂ X₃ -0.6 + 0.25d₃-0.6 * 9d₁ - 9d_1² 00-100 MT1/21/21/21/2 M_0.4 1/21/21/21/2 I1/2 TT1/21/2 MNZM^1/2

Reazioni e forze in equilibrio

10/01/22 K_a = 4ξ I_t/b Fx=0 H_F+H_A → ⇒ H_A=- H_F → Fy=0 V_F+V_A - 2qb₂= 0 ⇒ V_A = 2qb₂ - q_t M_D0 V_AZ0 → 3qb₂-qb_t- q_c2=0 ∑F_BA ⇒ ∑Fy=0 V_A=qb_t H_B = 3/2q_t+q_A X₁ N=0 N - q_B=H_F-q_bx₁