PROCESS DYNAMICS
and CONTROL
LAPLACE TRANSFORM
[ () ] = [ () ] = ()
[ () + () ] = () + ()
−1
[ () + () ] = () + ()
2
(2) =
()
⎡ ⎤
= () − (0)
⎣ ⎦
2 2
⎡⎢ ⎤⎥
() (0)
= () − (0) −
2
⎣ ⎦
∞
⎡ ⎤ −
1 where
⎢ ⎥
∫ ( *) * = () () = ∫ ()
⎢ ⎥
⎣ ⎦
0 0
−θ
[ ]
→
() = ( − θ) () = ()
PARTIAL FRACTION EXPANSION
2
+5+1
() =
(
+3
)
(
+2
)
() = + +
+2 +3
2 (+2)(+3)+()(+2)+()(+3)
+5+1 =
(
+3
)
(
+2
)
(
+3
)
(
+2
)
2
+ 5 + 1 = ( + 2)( + 3) + ()( + 2) + ()( + 3) −θ
−
when there is a , omit it during the inverse transform and add it after by writing τ
θ
−
instead of .
τ
FIND TF
write material / energy balances → explicit disturbances and controlled variables → create a
differential equation like → coefficient of y must be 1 → laplace transform →
' + =
find TF in Laplace domain → use table to convert in time domain
THEOREMS (LIMITS)
lim () = lim ()
→ →
∞ 0
lim () = lim ()
→ →
0 ∞
The time needed to reach steady state: = 4 ÷ 5τ
LINEARIZATION ( ) ( )
' ≃ ' + '
1
2
nd
2 ORDER SYSTEM
() = 2 2
τ +2ζτ+1
at open loop:
( )
τ +τ /2
● 1 2
ζ = τ τ
1 2
● τ = τ τ
1 2
τ
● 0
τ =
1 2
ζ − ζ −1
0 0
τ
● 0
τ =
2 2
ζ + ζ
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Process Dynamics and Control - Esercizi Svolti (Solved Exercises)
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Process Dynamics and Control - Esercizi e domande svolte (Solved questions and exercises)
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Process Dynamics and Control - Solved Exam Questions
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Process Dynamics and Control - Appunti ed esempi