Svolgimento:
Sia[math]S[/math]
la somma della serie indicata. Allora [math]S=-2sum_(k=1)^{infty}(-1/4)^k=-2 \cdot (1/(1+1/4)-1)=2/5[/math]
.
Serie: sum_(k=1)^(infty)(-1)^(k+1)1/2^(2k-1)
Svolgimento: Sia S la somma della serie indicata. Allora S=-2sum_(k=1)^(infty)(-1/4)^k=-2*(1/(1+1/4)-1)=2/5 .
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