k = 1
k = 2
Δ = | 1 k-1 | = -2k + 2k2 + k2| 0 k-2 | = k2 - 2k =| k 0 | k(k-2)
|A|≠0 k=0 e k≠2
|A|=0 c.e. k=0 e k=2
k = 0
- x-z=1
- 2z=0
- 2z=0
S={(1,4,1)∈ℝ3|4∈ℝ3}
k = 2
- x+2k-z=3-2k+2k=0
- 2x+2k=0
x+2k-z=0
- x+24-z=0
- z+k=0
- x+2=0
Δ = | 1 k-1 | = -2k + 2k2 + k2| 0 k-2 | = k2 - 2k =| k 0 | k(k-2)
|A|≠0 k=0 e k≠2
|A|=0 c.e. k=0 e k=2
S={(1,4,1)∈ℝ3|4∈ℝ3}
x+2k-z=0