Esercizi Teoria dei circuiti

Mutua1. Induttanza

: èhe 'eeee> è- .•L M'☆ mmm? 7. ?+ n ' 'Tiè T.si30/06/2021 Er QU=" Eh 7-< V=1- 50mAo =Re 1B 3A § kr8 =<^5 Rz 3= krR'6 6 Ks}n =, Rs 7 kr=Rs 5 kr=1 2 3 5 64( 00A -1 -1O entrante-1 corrente1 •r = O1O -1 D-1 -B 1• uscentecorrenteOO -111 ☐C 61 53 42↓G 1 1= =, 1 Aa 0,332 Rz 1 0,17 nelleVa3 * sempre posizioniR , -14 0,14 sulla diagonaleR non, 1① Dioa5 Rs6 0 O*È Ga Cri 1,3361A MS-16 -0,33 -1-= - =, 63Ga 0,70Ga -163 -16s -0,17-0,33B -- 1,31Gn61 G -16 -0,17-16s -1C -- }}A -90 VO MA E Ei= -== =0 O o0 00 OO NBA concorrenteancorateO 7D Es -segno --1O E acorrente o0 concede un 0 250Ae Osegno -Ì ( CraGE= -r( G -10.330 00 O-1 -1 0O 011 ==✓ ④0,33O-1O -1 d-OO-1 0.33-a17 0.200-0O -1 O 0,171 ^1 O 0.17 00-0.140,14 3×63×6 0.20④ o6×6-9( 9GE -10.33 O00= a✓ =dd-d- O0.33-a17 0.200 d S^ O -0.17 O0-0.14 7 3×1-3×6 D:0( A -5000-1 -1O1 :r = 0-1O -1 O O-1 00O -1 011 O 03×6 D 3×1:Gin ÌCRGE 599Cra -50 =- =- = D0 o -8S o-'i E fareT > la calcolatrice.= conÙ V593.92.63.3 203,7= =O2.63.32.4 134,2 }3.3 2.43.6 f 165.9-Crt ÙV = . ✓V 203,7 -37,8-1 O +165,91 -203,7= =i 69,5134,2 203,71 134,2-1 ☐ -165,9O -1165,9 31134,2 7-1 -1 ,165 -9 -165,9D 3×2 -a 1- O -134,2O -134 2-1 ,DD -203,71 203,7-- 6×3I A GIU E)+= -V -9E -28,8-37,8 =- -= 69.569,5 OO 31,731 7, 7165,9 -158,9-- d 134,2134 2 -- , O -203,7203,7-(G V E) -28,8 -28,81 =- = ④0,33 69.5 22,90,17 5,3831,70,14 -158,9 -22,20.20 -26,8④ -134,2O O-203,7 PotenzeI O mA28,8t= 28,8 '=- :d 22,922,9 PE 11 95,385,38 [O mW= )f-' = -259,229,8'.e = GD -22,222,2- / (PEG [ 7 ) mW-26,8 -22,2-26,8O 4 -155,64 ': : :-50 Gao V6 (PA 50Ag ) 10185mW-203,7=. . -=, = 4U

21/07/2021

[ 1=14 VEZ V12: 3mVA =B 0,0025gmi• Ri 50001=Rz 5000: a••1- e R 4000> = aRsi 1000 rPs 20001:6 6553 41 3 422 1 "G( Ge 2.100 0 0 -1 O1 1A ==r = "là2.Gz0 1 0 O 1 2-1B "À2,563 /-1-1O01 3-1C .- 1.10-3GsI "65 5.105 O06 0.0029pm(6)t' generatore3A 'comanda "colonna di chiCrtci ( Gr= "'( "RG }2.10 0O O 5.1J O-1.1J0 0 O -1 ae == È2. ' "2.1J -2.51J D0,0020 1 0 DOO 1-1 " "-72.10-3 Opj2.5.10 '-2.1J d-0e-1 g.O01 -1 -- 1-1-03 3×63×6 "5.10 0Don 6×6 5Crt(RG 1,5 0"} 00 OO 0 5.1J O -7 -0,5-1.1J == 10-3' O 00,45"2.1J -1-25.1J 0 10,002 -2,2O0 -"72.10-3 O05.1J O' -1 -75-2.1J d-0 -0,2390O 3×3-1316 D1 1--1O 16×3A-14 AE VEt O✓= ==El 12 OO 00O 0 OD DD0 0oT CRI( GE -✓= ?:LA" ' ]O perche "'( 0GE iO -140 0 5.1J O-1.1s:r }' Ala' "2.1J -75.1J -25,60 120,002 0O '"-22.10-3 0-5.1J 28,4' O-2.1J ao 3×13×6 O0:Ù ri I-1 (È -9,69I V3,23 0V O 3,23-1= i= = - =. ✓0 19,48 19,179,49t- --- 9,699,69 O 9,48O-1 0 -3,233×1O1-V6 MUIPA V6A 0,371 W -1O1 -6,46g. =.= = -19,17a -11( +3 I 6

30/06/2020

Ai 34mA=Aa 57mA: GVEri% p [ 19 V" 2 :Z 6i. Ri 8 ks:12 R2 S Ka-1- .• 8•-} '5 R 15 K} = aRG 5hr=Ps 0.4 Kr:RG D. Skr:73 61 542( 0 -1via 1-1 0 0-1- OB 0-1 0 11 1C O O 1 O 011 5 643 71 2G Gi 0,125=p iGs ①1a a O03 Gs 0,20I Gs 2.5s GGi 1,25Gz7 0,125È ( Gitti )-16 OG +62 0,5 -0.30- =: ,,( Gi) -63 -0,375-16261 -166+6-163 -1- , 63D 3,5-16s63 D 1-- A 0V MAEt -6E 0=i - =iEi -19 O 0- Ai 340D AzO 570 O0 0o O00o 71- GE( CRA= r -( 0v6 -11 O-1 0 0-1 -0,125 00 -0,2000,125- -0,125== 0O-1 O ^ ①11 1 0,125 0125 0,1250-1 OO O ^ 00 02.5001 01 O O10,20 2.5a 1,25 0,125( GE 0,75O 6✓ = -0,12s =00 -0,200 -0,125 - 18,25-190,125 0125 0,1250-1 o -19O0 02.50 0O1 :oCRA -91O0 -1 =1-1 0 0-1= - OO 00-1 0 11 1 34340 O 1 0 011 57:Ì 91,75-910,75 -= =18,25 O 18,253419 53- -Ù " CiVÌÈ ÙVa -172-1 V0 2001200 6565. .= = ii= ,, -35.5528,5828,58 O -1VB 1VC 6,976,97 O 1 -207,62--1- -200,650O-1 6,97O 0 1 -O 1 O 29,58 &O -1721 1- 15 VE =/ R2< È✗ -E =Ì A 2mA=.Vile I4s -=. 4WE 2 dradis=WA Mrsd3 /sin =Ri Gkr=Rz 11 kr=Li NU292=La 293 H/=) ALEE2/ (t ) V AartYenet )) Yaiwat+e +cos = cos= di tensioneSpengo generatoreil• ciocia:" 0,002: o> À A -45 0,00141