Analog electronics exercises

Determine: Vee

• Bias point;
• The type of feedback;
• Feedback gain beta;
• The A(OL) gain;
• The amplifier gainI 500µA voltage Av=Vo/Vs;
• Q2 Rin(CL) and Rout(CL);
• Rs Rin and Rout;c Qi1k

Data: Vcc=12Vits Rs=1kOhm, Re=1kOhm,Rl=4.7kOhm, Rf=36kOhm,I=500uA;Q1=Q2=Q:Rf beta0=betaF=beta=100,Co Vbe=700mV, Va=50V36k JoRRE1k 4.7K1.

Vee Iea iIE IIea IdaIsa ea Ver VE WiseIse RE RfI 500µA iVerIeri te TIBI BEora aaIz FIBIIe Isat PIÈ eVEVere WiseVer Visep RE Rf aRf PtiRf36k PIÈ_PIÈre tcpfjretcpfffrea Fe.eecp1k V ftp.tfa padrep re reVer I tkeffy fa tcptbretlpi.HRa lpi.fr876,86mVEVer MA876,86T.ee IERE IVistiver 4.91 491µAFIB EMA IeIsi Ia RfIeri i88Ietto MA1,77a a MAIIna 8,82Iea EPtiVce E VTUBEVez 1,58Vce eP perVeer VVeeIB MAIce 11882 12iQi MAIUei i941I V 15 8ee eii Vi iterVeeQr l'A8 82Il 12ee2.

Q2Rs Qi1kits Rf36k JoRRE1k 4.7KFeedback topology: shunt-shunt; Q2Rs Qi1kits Rf36k JoRRE1k 4.7KQ2QiOs Rs1 se Rs 1k Rf36k JoRRE1k 4.7K3.

eteroI Yacht 42292lart1 i 36kI 92Re1kYuri tra27,78M P1 27784,1Iilè aRe9ai Rf OJa O otra RII Tieio 1,03mF421_ 27,78415iz ae 1I JrRfJa Ji0 OQ2Qrliis Os RsRs 1k 36kPoi itti r4.7k972,974.

02its Qi ofliOs Rs1 se Rs 1K 36kPoi itti r4.7k972,97A Et.ir io ifaissmaltii ReN n QQ0È a Ima Retript 9178mi V AT.it f2uatlPtDl4rriNRl aa VNN Yi A816,83Rs 2M EaA tira Ai741.54kVi aa5. tua È i1È faa aAtr 1 134,33kVe AIIPiÈ ÈAv 1 VV3433È fa aa a6.

ERII.rs 4i'NZu i816.831 i459,4Ratt rit 2Eraggiro2oz t RIRIN 37,81 liEa Aiip iRothRotta 21,27 2a t.in p17. RI RothRIN Ronis Rs RiB IRII iRstrsn RIN 39,3Eµ è 2aRitrovi iRootsRotti è 21.371µe r

Determine: open loop gain and beta-network gain

• Open loop gain andbeta-network gain;
• Voltage gain;ke
• Input resistance;RC3
• Output resistance;ke 10kRe Oo

Data:7.5K RC1=5kOhm,Rei Rout RC2=7.5kOhm,5k RC3=10kOhm, R1=200Ohm,R2=330Ohm, Rs=600Ohm,Rs RF=20kOhm,beta0=betaF=200, VA=125V,600 IC1=250uA, IC2=1mA,Ts IC3=500uA.Rim RF20k RRi a3302001.

Small signal parameters

Let’s calculate small signal parameters: IeIei IeaGma Inna Imsa4dmè è è10ms 20msVt Vt Vtri5k20ktEma Tra te pgom.EIOK.cipgom.atPgm 500ktVi Vi vi125ha 2250ktE ETae roar roseIei IIeriFeedback: there is a current mixing and current sampling, so this is a series-series feedback.

It’s a transconductance amplifier (z-parameters): i12ZrZiiVi te ZaiaZaie tThe beta-network is: re ii ioi c'e 20k 92di R tra330200 ritiri EtraviZii 198,051e eil izzo 3R2 traR 2Zz it Pize RattretriedI 0LLAJ2 ILZa 3 2R2a e fil Reµizzo rapire Eva 324,71Zaza Riain i e

The equivalent small-signal circuit with the equivalent model of the beta-network is:Re Oo7.5K RcsRei5k 10kJBRs Fa600Ts I Zu Zu324,7198,05 SiPiaTo calculate the open loop trans-conductance gain, we consider: beta=0 (and “delta” parameter negligible):Rcs10kRe Oo7.5KNei5k JBRs Fa600Ts I Zu Zu324,7198,05Piztè io fa EFaio e 2,66M8m32cm Eio a tu peti 222VB VE V818ms 272reffrttstzzzcpr.tle Write 398 V VENei8miae 8m27I t tzacpi.tlriti VVvs E 0,99a PetiInnitits Rst ZiiA io fae Faio ae 881 391 0,992,66mi 272Vi6 031E E Vi296,22mA1 Èe piopen loop gain and beta-network gain are:So, È iV P6 O 3A 23 rI1 a a2.

Vit.EE 2,96kVtra resa a3.The equivalent block-diagram circuit is:el RinRin IReRs R t600its P iRii RisiRinns trim Rsa citaterii rii ipe Erii 59,81petitu KZue rt 17RI Risi Bit 1,22141a aèRisi Rat Rit riRin I 22Ma4.The equivalent block-diagram circuit is: iRi t oRERs Rout600 Rlitsµ Print Rattµ RouteÈe that atutto ea Ratti t.ie P aIl t.ie P eRe 320 65 Kr

Determine: bias point, voltage gain and output resistance

• Bias point;
• Voltage gain;
• Output resistanceke ke and wH,Rea considering onlyRk Cc=2pF;

RB elRc22kRok Data:Ce Vcc=12V,2Rs Rs=33kOhm,Rb1=120kOhm,Cs i Rb2=12kOhm,33k Rc=22kOhm,Os 12132 Re1=1kOhm,12k Re2=12kOhm,RE RL=10kOhm,1k RF=150kOhm;Q1=Q2: |Vbe|=0.7V,BetaF=Bet0=100,r0->+inf.RF Consider Cs and CLOo as short and Cc as150k an open in theRi frequencies of10k interest.1.

DC analysis

DC analysis: VÀ VVa 1 09avec RaeRiz RBtke ke Rea èUrbeRthk 10,91ktRaRkRB Re22kRok ViseVtb IBReef PetiIisore 0ai Vtb 8µAVisti 3,4IB Irift petiRERise12k E 348 IOMAIe 35mAPe IisRE1k Ire Iei Idae Vee PittVee ReaIre VersIsaa Re WEBFtlRea Bz ReIei IdaVEBIsa FtlRea Re ti IeiIn REGGIE f 5,64µAIeiIn t.reqfpethf.itE564E MA 0,56mAPi IbaIca e è ViVee Iei PrVee Ida 4,12IB tiReRee E VVeer IdaVee 16Pr 5Rea 1Q ViVee 4,12Ie 0,35mAe ViQr IeaVeer 5,16 0,56mA Ice EIm 22,4mi'sIei 14mFe II Vtp ua.amra ae 8mi702Io 0 at2.

AC analysis

AC analysis: ReaRkRe22K 2Rs i33kOs RB10,91k RE1kRF Oo150k RlOkRBERB.tl 10,91ktRezaType of sampling: voltage;Type of mixing: current;Type of feedback: shunt-shunt.

Beta network:RFii l'of Poolii viae150k Riftorit iSitiio e_ ftp.qootOie 1iiPe 6,674ERiRita 150111 e al'if ttf RF0Joe Tifo8 iRE1 Rafa 150111iot 6,674E 0oz eea tif RE ofe OTifOaf0Equivalent beta-network small signal circuit:Rif Raf150k 150kProf goofEquivalent small signal circuit: Rea12kRe22K AlQiRsOs RifRBii 150kRs Prof33k 10,91k REIk OoRiRaf 150kfool 10kREaa5,26kri RLNR.tteriRsrRsNRBNRifE7,77k.ri OoJA lioraor5 5,26KReQ 22k12is.is sRs 7,77K RE1kIoiii II iois E 991,58mVsomari Viso eJA Itgmzrivjja VV8mreplrurtricp.tl E 19,728miI REt IRINITIE diPoti 7,25kVtre E tite 141,77kVI io1 t.IE Ai72,87kVaa t.IE p VT1 V2,21Is faaa3.

ir.it feti 249,55RINITIa eI E 26REIRoute 128 re A ptiRail RiN 12h RoutRi Routr ea 12hRout12 t i Rout riIfrRoute 129,931È t apCei ce 1 cefif a smfefkgqi.tt IlPothIfa4H4rFiCe o i2nFle le1Ce Èe eEWii reieitreaeef.liRINI RedPotuta Kr7Tait 25Refe Rettili tilttrillo ike21,13Rei eWII cè E iE 73kHz4642,92 24threadReteRiace sEèWii iWE 904i kHz2TAP 5,6814radt s

Calculate: Re, bias point, voltage gain and output resistance

• Re such thatVc2=11V;
• Bias point;
• Voltage gain;RE
• Output resistance;
• An estimation of wHconsidering only:I 5M Jo Cc=5pF;

VezQRs Data:Cs CsQ Vcc=24V, Ip=1mA,47K Rs=47kOhm,le RReOs Rc=12kOhm,12k 10kRout RL=10kOhm,Rf=1.5MOhm;Q1=Q2: |Vbe|=0.7V,BetaF=Beta0=100,r0->+inf.1.

Iei 916,674.1e i 9,17MtIda Ee è 1,01mAIei IpBata iIei IfIbi E 0,1141a PE EIIIE t.cat 935,94µA2 pt VisitVee Rieti 8,71ktRe a èIE2.

ViVee VEREIVee Re 15,15Ea Vee ISV15 ii 1,01mAIc e E V4Vee Ver 85Veer RE lea 4,8 SUOra Veci iLcr 916,67ft3.

Imi Iei 36,67mi40,4M ee Vt anniÈ ÌCurrent sampling and current mixing. It’s a shunt-series topology:Fifty Riotl'ofeiii ifI 5M fattift 822 l'ofttf OafREOif 8.71k iTRE 5MUil RE IRitz let e 2iii roofiP 5,77miREaiie Ee z REi t Ret0eOifS 5,77miReOafa REGif RetOfi E 8 86112ReliefJoeRafa el'of 0tifa Fioj.IEioa Raf 8178,86konJj QiQiRs Ritis.it Re RlI47k 12kRs 5M 10kPiafE IeriNRL 5,45Re viMA183,49tÈ rejaa V613,24mVRenziIma Eja z Gma RafI t ViVa 26kVRofl8mi 36Tart Potia05 tiE 2,35kVRSN RiflettieÈ E Ai9,59ktFaio Tja 70,23A itir t Aii is teapis ioa tea TÈtv Retta 1Èa aRsV V20,484.

0 KrReRout iea5. EWu CiReali lelN 5pfireqareNRE545k.sieSIWilt i2T 84MHzè 36,6714rad 5Ren ee

Determine: bias point of all transistors

• Bias point of all transistors;
• Voltage gain Av;Vee Vee
• Input resistance;Rout
• Output resistance;Re to
• The loop gain using cut method;ri 6kRin Cs

Data:6KRs Vcc=24V, Rc=6kOhm, Re=700Ohm,RCs Q Rf=6kOhm, Rs=600Ohm,l600 3k RL=3kOhm;Js Q1, Q2: Vbe=700mV, betaF=200,beta0=400, rPi1=10kOhm,2 rPi2=5kOhm;Re7001.

DC equivalent circuit

DC equivalent circuit:Vee Vee iIE Vista 1mAa aREReRE 6k PittIE IFIisIE PiIta tit a a6K Ii Ie IisIcetIe PeatQ 2 VieVee ReteIi eq aReRe Per LUBEVee Re1,32Ii700 Reoa aRFVee Rete Iii LUBERePer Iii aRe iRepeal LUBEVee II IePrReti 1re iIII Piallati PerVee LUBEtre Ietre tre a REI PiallatiVee LUBEtre IEIF tre tre aa 5,07141EPeteIe 1,01mAe 23 ViVistaVeeVee e 3e Piaf E 3,81mAPittiPia IBIe IePer IbraIeri e e eRette E ViVeer avec rete IcaVee 1 11taliQi Vee Vi 1,01mA23,3e 1 I Krrunrun 10k 2e esmi.IE 80mA8mi 40msI i iIo 2ozo o2.

AC equivalent circuit

AC equivalent circuit: 9Rs RIQi600 2KJs 2Re700 Ri6kÈRi Retire 2kType of sampling: voltage (shunt sampling);Type of mixing: current (shunt mixing);Type of feedback: shunt-shunt.

Rt ioiii troop4 tifit6k tottif iote4aoittlzzo.fi6kt Ivia 66,67MRe peRit iie e r al'if RETifaOaf Ii 66,67M CokeRafaf Joe Ree ir al'ofJit Riaol.ro vitaEquivalent beta-network circuit: RafRip6k 6kprof profEquivalent AC circuit with equivalent beta-network circuit: 9è Raf riQi 6kPool 2kJaRs RifDis 6kRs Pool600 OraRe700E osiA o I isis VV8mi Rotti rito 120aava ERenzie Vi8mi 960,88mVva a RenzieImOs 1 tRSNRiftlruitRENru.dk V44,3 A5atia EÈ AiEA 62,76kVIio e EAti 5,48kVt.FI 1a AIIPittre ViEt.FI 9,13Tèa is a3.

9à Raf RiQi 6k 2kPoolJaRs RifDis 6kRs pool600 OraRe700oh tlRENrurXPoztDIr5RSNRifnt.ru riRin 44,3e 47Rin ERina 51a t.PE PiRin Naim Rs RinRs Rsa Rim 125Rst i Rin rimorsi lÈ Iitra 5851E 24.

9à Raf RiQi 6k 2kPoolJaRs RifDis 6kRs prof600 QiRe700Raitt RiRot N 1 Kr5a e IREIRiti iE 130,9e eftp1tRione NRout Rout RiRiR e ea RLIRout tra t Route riE 136,871Router.irè Ète ar5.

9Rs ria600 2K2RE700 RE6k oAoBRs ria600 2K2JtR tua Sxe700 5ke a Eri1Rt reA pingRETERsf6k te eai1 p It iIt Ot È IIoit D l20VVffT8mafrinfretfrsplnitlrenrudlp.itf e 90NETOr è VI2mV7RettutakpoitiRsa trsNCruitlrethitrkp.itVA RE Viè8mi Renzie 963,19mVOt a RENZII t 8miJp t.peT faÈ IIe10,49

Determine: feedback tipology and beta-network parameters

• Bias point;
• Feedback tipology andbeta-network parameters;Vee
• Voltage gain;Re500

Data:Rs=10kOhm, RF=10kOhm,Ip Re=140Ohm, RL=500Ohm,Qr Vcc=15V, Ip=200uA.Q1=Q2:i BetaF1=BetaF2=Beta01=Beta02=100, Vbe=0.7V, Va->+inf.Rs Re o10k 10 kOs RE1401.

70IrsVee MAVise a125Vee Re Vere500 Irs Rst Rete eIp Irs Ieri IeRERsteQr eQ fIpzPetlT.rs 2stRi 2 aERFVE2zIRSRstrr.INRs Re pete RE10k 10k RE ftp.Ie.KR.ttIrsRs140 trea RpIEziVEzf2stRFIplBetl i1 RilPttDPiIBiiIBi rsRs.IrsT.rsfa VEij2stRFIp RilPttDPitlBrT.rs IrsVEajIrsRs RilPt.tDP