Formula
n3 + 1n!· (n/4)n = anan+1an = (n+1)3 + 1·(n+1)n+1·n!·4n(n+1)!·4n+1·n3 + 1 = (n+1)3 + 1·n!·4n·(n+1)u+1n3 + 1·(n+1)!·4n·(n+1)4 = 1·1·1·(n+1)u+1n+1·4·4u+1 = ·(n+1)u4·4n = 1·(1 + 1/n)n4 = >e4
n3 + 1n!· (n/4)n = anan+1an = (n+1)3 + 1·(n+1)n+1·n!·4n(n+1)!·4n+1·n3 + 1 = (n+1)3 + 1·n!·4n·(n+1)u+1n3 + 1·(n+1)!·4n·(n+1)4 = 1·1·1·(n+1)u+1n+1·4·4u+1 = ·(n+1)u4·4n = 1·(1 + 1/n)n4 = >e4