Esercizi Svolti e Commentati:
Microelectronics (B. Razavi, Wiley 2014)
Capitolo 9 Cascode Stages e
Current Mirrors
Parte IV
39.
Iref = Ic,ref + I / p = Ic,ref + 1/p (Ic,ref / p + IcQ1,1 / p + IcQ1,2 / p)
IcQ1,2 = 6/2 IcQ1,1.
IcQ1,1 = Ic,ref / 2
=> Iref = 2 IcQ1,1 + 2 IcQ1,1 / p2 + IcQ1,1 / p2 + 6/ p2 IcQ1,1
= IcQ1,1 (2 + 9/p2)
IcQ1,1 = Iref / (2 + 9/p2)
IcQ1,2 = 6 IcQ1,1.
40.
VDD = 3V
VTH1 = 0,4V
kn = 20 uA/V2
R = 1k
IREF = 2uA.
VGS1,REF = sqrt(2 IREF / kn (W/L)) + VTH = VDS = VDD - IREF R.
IREF = 1/2 kn (W/L) VOV2
(W/L) = 556.
41.
If IO = 10 uA => (W/L)2 ?
IO = (W/L)2 / (W/L)REF IREF. => (W/L)2 = 5 (W/L)1.
43.
lambda != 0
M1, M2 identical
IREF = (1/2) mu_n Cox (W/L)ref (VGS,1REF - Vtn)2 (1 + lambda VDS1)
ICOPY = (1/2) mu_n Cox (W/L)copy (VGS,1copy - Vtn)2 (1 + lambda VDS2)
IREF = ICOPY => (W/L)copy (1 + lambda VDS2) = (W/L)ref (1 + lambda VDS1)
IREF = (kN/2) (VGS,1REF - Vth)2 (1 + lambda VDS1) VGS,1REF = VDS,1REF.
= (kW/2) (VX - Vth)2 (1 + lambda VX)
sqrt(2 IREF / kN) = (VX - Vth) sqrt(1 + lambda VX)
IO / IREF = ((W/L)2 / (W/L)1) ((1 + lambda VDS2) / (1 + lambda VDS1)) = (1 + lambda VD2) / (1 + lambda VGS)
IF EDGE OF SAT. VDS = VOV
=> IO / IREF = 1 - (lambda VTH) / (1 + lambda VGS) = 1 <=> (lambda VTH) / (1 + lambda VGS) << 1
=> VOV >> -1/lambda => VGS > Vth - 1/lambda
44.
A) RE = 300Ω
VBE1 = VT ln(IC/IS) = 0,732V
Vb = VBE + VE = 1,232V
ROUT,A = (1 + gm1 ro1)(RE || rπ1) + ro1
≈ gm1 ro1 RE
Ibias = 1uA
VRE ≈ 0,5V = VCE2 (Q2)
B) ROUT,B = (1 + gm2 ro2) ro1 + ro2
≈ gm2 ro2 ro1
VBE1 = 0,732V
VBE2 = VBEQ - 0,5 = VT ln(IC/IS)
Vb2 = 1,232V
45.
ROUT = 200kΩ
Ibias = 0,5uA
A) λ = 0,1V-1 => (W/L)1 = (W/L)2?
B) Vb2 ?
ro1 = ro2 = 1/λID = 20kΩ
=> ((ROUT - ro1)/ro2 - 1) 1/ro1 = gm1 = 0,0004 S = (2,5kΩ)-1
gm1 = √(2 ID un Cox W/L)
=> (W/L) = gm12/(2I0unCox) ≈ 1,6
B) Vb2 = √(2ID/(un Cox (W/L))) + Vth = 2,9V
46.
Av = 500beta = 100Av approx -Va/(VT + Va/beta) => Va^2 + Va(VT/Av) + (AvVT)^2 = 0.
Av approx 9,quasi 10, quasi (80,1 kHz)
VA approx 0,65V
VIN,BIAS = VT ln(IBIAS/IS) approx 0,71V
VCE,1 = 0,5V = VC1
VB1 = VBE1 + VE2 = VBE1 + VC1 = 0,71 + 0,5 = 1,21V.
47.
P = 2mW VCC = 2,5V.
A) VB2, VB3 -> Q1, Q4 VBC = 0,2V
B) Av = ?
IBIAS = P/VCC = 0,8 uA.
VBC1 = VB1 - VC1 = 0,2
=> VC1 = VB1 - 0,2
VB1 = VBE1 = VT ln(IC/IS) = 0,725V
VC1 = 0,525V
VBE2 + VC1 = VB2 = 1,25V
VCB4 = VC4 - (VBE4 + VE) = 0,2
VC4 = VCB4 + 0,2 + VE = 3,425V.
VB3 = VCC - 0,725 = 1,775V
Av = -gm1 (gmi2 ro2 ro1 || gmi3 ro3 ro4)x 740
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Esercizi stadi Cascode e specchi di corrente - Parte II
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Esercizi stadi Cascode e specchi di corrente - Parte III
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Esercizi stadi Cascode e specchi di corrente - Parte I
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Esercizi stadi Cascode e specchi di corrente - Parte V