Concetti Chiave
- The program converts an integer into binary, octal, and hexadecimal formats using separate functions for each conversion.
- The main function prompts the user for input and manages the conversion process, repeating until the user decides to stop.
- Each conversion function calculates the representation by dividing the number and storing remainders, which are printed in reverse.
- The program employs a `do-while` loop to repeatedly prompt the user and perform conversions based on user input.
- The conversion results are displayed to the user, and the screen is cleared for a new input after each cycle.
#include
#include
void binario(int n);
void ottale(int n);
void esadecimale(int n);
int main()
{
int n;
char risposta;
do
{
cout
cin>>n;
if(n
cout
else
{
binario(n);
ottale(n);
esadecimale(n);
cout
cin>>risposta;
system("cls");
}
}
while((risposta!='n') && (risposta!='N'));
return 0;
}
void binario(int n)
{
int A[100],c=0,i=0;
cout
if(n==0)
cout
else
while(n>0)
{
A[c]=n%2;
n=n/2;
c++;
}
for(i=c-1;i>=0;i--)
cout;
cout
}
void ottale(int n)
{
int A[100],c=0,i=0;
cout
if(n==0)
cout
else
while(n>0)
{
A[c]=n%8;
n=n/8;
c++;
}
for(i=c-1;i>=0;i--)
cout;
cout
}
void esadecimale(int n)
{
int A[100],c=0,i=0;
cout
if(n==0)
cout
else
while(n>0)
{
A[c]=n%16;
n=n/16;
c++;
}
for(i=c-1;i>=0;i--)
{
switch(A)
{
case 10: cout
break;
case 11: cout
break;
case 12: cout
break;
case 13: cout
break;
case 14: cout
break;
case 15: cout
break;
default: cout;
}
}
cout
}
Domande da interrogazione
- What is the purpose of the program described in the text?
- How does the program handle the conversion of numbers to different bases?
- What mechanism does the program use to continue or terminate the conversion process?
The program is designed to convert a given integer into its binary, octal, and hexadecimal representations. It repeatedly prompts the user for a number, performs the conversions, and displays the results until the user decides to stop.
The program uses separate functions for each conversion: `binario` for binary, `ottale` for octal, and `esadecimale` for hexadecimal. Each function calculates the respective base representation by repeatedly dividing the number and storing remainders, which are then printed in reverse order.
The program uses a `do-while` loop that continues to prompt the user for a number and perform conversions until the user inputs 'n' or 'N' in response to a prompt asking if they want to continue.
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