MDOF system dynamics
n degrees of freedom → n independent variables qi to describe system conf. {qi} generalized coordinate vector.
M ODE, scalar → matrix form.
Vibrational modes
- Natural freq.
- Modal damping factor
- Mode shape
Description of the way the system vibrates at each natural frequency: it represents relative displacement of all parts of mech. system for a particular mode.
Mode shapes
"Normal" modes, Ψ ∈ ℝm.
"Complex" modes, Ψ ∈ ℂm.
Damping distribution determines whether modes are normal or complex.
- Undamped system, very lightly damped or proportionally damped exhibit normal modes.
- System with much localized damping exhibit complex modes (ex. cars with shock absorbers).
Linear and natural mech. system
Kinetic energy can be expressed as a quadratic form of velocities.
MDOF system dynamics
Degrees of freedom — independent variables qi to describe system conf. {qi} generalized coordinate vector.
ODE, scalar → matrix form.
Vibrational modes
- Natural freq.
- Modal damping factor
- Mode shape → eigenmode u(i).
Description of the way the system vibrates at each natural frequency: it represents relative displacement of all parts of mech. system for a particular mode.
Mode shapes
Normal modes, Ψ(i) ∈ Rn.
Complex modes, Ψ(i) ∈ Cn.
Damping distribution determines whether modes are normal or complex.
- Undamped system, very lightly damped or proportionally damped exhibit normal modes.
- Syst. with much localized damping exhibit complex modes (i.e., cars with shock absorbers).
Linear and natural mech. system
Kinetic energy can be expressed as a quadratic form of velocities.
1) n = 2
[ q1 ] [ x1 ] [ y1 ] [ q2 ] [ x2 ] [ y2 ]
Different sets of coordinates are available, we choose the first { qi }.
( [ q1 ] ) ( [ y1 - y2 ] ) [ R1 ]
( [ q2 ] ) ( [ y2 - y1 ] )
Relative displ. of Mi w.r.t. M2.
- Generalized coord. vector { q }.
- TBD... (check theory book).
- EOM. Dynamic balance of each mass (Newt. 2nd law).
Rearrange equations -> grouping: ( L/2m x1. + x2· x1· x2 - x2 + x1 + x2 )
Conversion into a matrix form
Particular cases:
- Unforced: {F} = {0} HOF UNAMPED FREE RESPONSE.
- Undamped: [C] = [0] [M] { qi''} + [K] { qj} = 0.
Properties of [M] and [K] matrices
Constant and real coff.
Symmetric?
We can always get sym. matrices for a natural mech. system with Lagrange's approach, always sym.
Neutral "S" we can get non-sym. mech.
Positive definite and positive semi-definite (P.s.d.).
A square matrix [A] is P.D. if ∀ {z} ≠ {0} ∈ Rn and {z}i ≠ {0}, {z}T[A]{z} > 0 strictly positive scalar quantity.
A square matrix [B] is PS-D if ∀ {z} ≠ {0} ∈ R, {z}T[B]{z} ≥ 0.
[M] is P.D. and [K] is P.S.D.
Example: Consider a system of N masses connected by springs
Kinetic energy: T = (1/2) ∑ mivi2.
Absolute velocity of mi.
T = 1/2 {V}T[m]{V} > 0 ∀ {V} ≠ {0}.
Matrix expression quadratic form of velocities.
{V} = [v1 ... vi ... vN]
[m] = diag (m1, m2, ..., mN)
Potential elastic energy: V = (1/2) ∑i=1 to N-1 ki(xi,j)2 (x is Spring change).
V = 1/2 {x}T[K]{x} ≥ 0 if the system allows rigid body motion.
∀ {x} ≠ {0}
{x} = [x1 ... xi ... xN]
2-DOF example
{x} = { x1 x2 }
{v} = { v1 v2 }
u = x1 - x2 → V ≠ 0 if {x1 x2} ≠ {x x}
i.e. when x1 = x2 = x → u = x1 - x2 = 0.
Translation of the system w/o spring deflections.
T > 0 ; V ≠ 0.
v = { v1 v2 }
[m1 0] [x1]
[0 m2] [x2] [K -K] [x1] {0}
[x2] -K K [x2] = {0}
V = 1/2 K (x1 - x2)2 = 1/2 1/2 [x1 x2]T K [x1 x2] = 1/2 [x1 x2] [Kx1 - Kx2] [Kx2 - Kx1] = K [(x1 - x2)2 - x12 - x22 + 2 x1x2] = 1/2 [ (x1 - x2)2 ]
Sylvester criterion (...)
Example (theory back).
Eigen value problem (EVB) (...)
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