Statically indeterminate structures and frames
In static analysis, a structure is statically indeterminate if the static equilibrium equations are not sufficient for determining the constraint reaction. This means that the number of unknown reactions is greater than the number of equilibrium equations. In such a case, the structure may be solved by taking into account its stiffness characteristics, which requires material information.
Analysis methods - force method vs displacement method
Structural analysis requires that the equations governing the following physical relationships be satisfied:
- Equilibrium of forces and moments
- Compatibility of deformations
- Constitutive law (→σ)
Force method
The force method converts the indeterminate structure to a determinate one by suppressing a sufficient number of constraints. These are replaced by the relevant generalized forces (unknowns), enforcing compatibility to find the unknowns. In other words, among the infinite number of balanced configurations (n = number of unknowns), the only one which also satisfies compatibility is retained.
Example
Actual structure
- Xa
- Ya
- F
- YB
Primary structure
- Primary structure → Structure
- YB
Equilibrium condition
Σx = 0 → XA= 0
Σy = 0 → YA + YB = F
In such a case, the structure may be solved by taking into account its stiffness characteristic (thus material information is needed).
Analysis methods - force method vs displacement method
Structural analysis requires that the equations governing the following physical relationships be satisfied:
- Equilibrium of forces and moments
- Compatibility of deformations
- Constitutive law (ε-σ)
Force method
The force method converts the indeterminate structure to a determinate one by suppressing a sufficient number of constraints. These are replaced by the relevant generalized forces (unknowns), enforcing compatibility to find the unknowns. In other words, among the infinite number of balanced configurations (n = number of unknowns), the only one which also satisfies compatibility is retained.
Example
Equilibrium condition
ΣX = 0
ΣY = 0 → XA + YA - F = 0
ΣΓ = 0 → Ia + F a - F (a + b) = F
Compatibility condition
The compatibility condition means that point B must not move → γΒ = 0
N.B. Primary structure is arbitrary and must be statically determined.
Compatibility condition
YB=0
YA+YB=0-YA+YL=0
YB=F EI-YA+F EI=0
0=F EIYB=F EI I F EI=0YB-3EIYA=F F-YA+F FYA=F EIYA=YB-2EI 3=0=I=0YB=3F EI
Degradation method
The degradation method consists of finding the only forces that meet the condition among the loaded ends, providing valid deformation compatible conditions. This method is used for continuous structures where valid deformation compatibility conditions are sought.
We start from the complete displacement:
- Inductive collapse axis
- S1F = EAN1 = EAN = FE1 = EAS = SA = SB
- Complete Fx
- Force diagram single beam Fx = 5F = NN = M + HMN1 - F = 0A
Now we place the equilibrium (Continuum)Ƹ (F/EI) = Ƹ (F/EI) Ƹ (EAı / EAı) Ƹ (EAı / EAı). Frames have bending and some rustiness because there are rigid frames, and they can translate ➔ they can translate.
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